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Gennadij [26K]
2 years ago
6

Which two statements are true of electromagnetic waves?

Physics
1 answer:
Snowcat [4.5K]2 years ago
4 0

Answer:

Where are the statements mate?

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A length of copper wire has a resistance 44 Ω. The wire is cut into three pieces of equal length, which are then connected as pa
WINSTONCH [101]

Answer:

\frac{R}{1} = \frac{44}{9}\ohm

Explanation:

Let us imagine that there are three wire of length equal length having equal resistances each of 44/3 Ω

Now connect these wires in parallel to so that their equivalent resistance is R.

then

\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

\frac{1}{R} = \frac{3}{44}+\frac{3}{44}+\frac{3}{44}

\frac{1}{R} = \frac{9}{44}

⇒\frac{R}{1} = \frac{44}{9}\ohm

5 0
3 years ago
Read 2 more answers
A railroad car is pulled through the distance of 960 m by a train that did 578 kJ of work during this pull.
Wittaler [7]

Answer:

<h2>602.08 N</h2>

Explanation:

The force supplied by the train can be found by using the formula

f =   \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{578000}{960}  \\  = 602.083333...

We have the final answer as

<h3>602.08 N</h3>

Hope this helps you

7 0
3 years ago
What is the force required accelerate a 5.0 kg object at 3.0m/s^ 2?
NeX [460]
The equation to find force is f=ma. So, if you plug in the information that you have you'll get F=5x3 and that'll equal F=15N
6 0
3 years ago
Choose all the answers that apply.
Serhud [2]
<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force


</span>
8 0
3 years ago
A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potentialenergy func
OlgaM077 [116]

Answer:

A= 148.92  m/s²

Explanation:

Given that

U(x,y) = (6.00  )x²  - (3.75  )y ³

m= 0.04 kg

Now force in the x-direction

Fx= - dU/dx

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dx= 12 x

When x=0.4 m

dU/dx= 12 x 0.4 = 4.8

So we can say that

Fx= - 4.8 N

From Newtons law

F= m a

- 4.8 = 0.04 x a

a = -120 m/s²

Acceleration in x direction ,a = -120 m/s²

In y -direction

F= - dU/dy

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dy = 0 - 3.75 x 3 y²

When y = 0.56 m

dU/dy = - 3.75 x 3 x 0.56 x 0.56

dU/dy = - 3.52

So we can say that force in y -direction

F= 3.52 N

F= m a'

3.52 = 0.04 x a'

a'=88.2 m/s²

acceleration in y direction is 88.2 m/s²

The resultant acceleration

A=\sqrt{a^2+a'^2}

A=\sqrt{120^2+88.2^2}

A= 148.92  m/s²

7 0
3 years ago
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