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monitta
2 years ago
12

Need help with physics please

Physics
1 answer:
bazaltina [42]2 years ago
4 0

The centripetal force : F = 293.3125 N

<h3>Further explanation</h3>

Given

mass = 65 kg

v = 9.5 m/s

r = 20 m

Required

the centripetal force

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

r = radius, m  

Input the value :

F = 65 x 9.5² / 20

F = 293.3125 N

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If the momentum of a system is to be conserved, which must be true of the net external force acting on the system?
kari74 [83]

Answer:

D. zero

Explanation:

For momentum of an isolated or closed system to be conserved (initial momentum must equal final momentum), the net external force acting on the system must be zero.

There is always external forces acting on a system, for this system’s momentum to remain constant, all the external forces acting on the system must cancel out, so that the net external force on the system is zero.

F_{ext} = 0

Therefore, the correct option is "D"

D. zero

7 0
2 years ago
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
rusak2 [61]

I'll bite:

-- Since the sled's mass is 'm', its weight is 'mg'.

-- Since the coefficient of kinetic friction is μk, the force acting opposite to the direction it's sliding is    (μk) times (mg) .

-- If the pulling force is constant 'F', then the horizontal forces on the sled
are 'F' forward and (μk · mg) backwards.

-- The net force on the sled is  (F - μk·mg).
(I regret the visual appearance that's beginning to emerge,
but let's forge onward.)

-- The sled's horizontal acceleration is  (net force) / (mass) = (F - μk·mg) / m.
This could be simplified, but let's not just yet.

-- Starting from rest, the sled moves a distance 's' during time 't'.
We know that  s = 1/2 a t² , and we know what 'a' is.  So we can write

           s = (1/2 t²)  (F - μk·mg) / m    .

Now we have the distance, and the constant force.
The total work is (Force x distance), and the power is (Work / time).
Let's put it together and see how ugly it becomes.  Maybe THEN
it can be simplified.

Work = (Force x distance) =  F x  (1/2 t²)  (F - μk·mg) / m
 
Power = (Work / time) =    <em>F (t/2) (F - μk·mg) / m </em>

Unless I can come up with something a lot simpler, that's the answer.


To simplify and beautify, make the partial fractions out of the
2nd parentheses:
                                   <em> F (t/2) (F/m - μk·m)</em>

I think that's about as far as you can go.  I tried some other presentations,
and didn't find anything that's much simpler.

Five points,ehhh ?


4 0
2 years ago
Read 2 more answers
How would radiation occur in space?
Marizza181 [45]

Answer:

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Explanation:

3 0
2 years ago
What is the voltage of a motor that draws a current of 2 a and produces 240 w of power?
MA_775_DIABLO [31]
Here Power = Voltage * Current

So, Voltage = Power/Current

Put the values, 

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In short, Your Final Answer would be: 120 Volts

Hope this helps!
8 0
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A gas-turbine power plant operates on the simple Brayton cycle between the pressure limits of 100 and 1600 kPa. The working flui
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Answer:

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Explanation:

See the attached picture below for the solution

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