The velocity of sound in at 300C is 511.3 m/s.
Explanation:
The equation that gives the speed of sound in ar as a function of the air temperature is the following:

where
T is the temperature of the air, measured in Celsius degrees
In this problem, we want to find the speed of sound in ar for a temperature of

Substituting into the equation, we find:

So, the velocity of sound in at 300C is 511.3 m/s.
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Answer:
4.29 millimeters
Explanation:
Bats emit ultrasound waves: in air, ultrasound waves travel at a speed of

The frequency of the waves emitted by this bat is:

Therefore we can find the wavelength of the wave emitted by the bat by using the relationship between speed, frequency and wavelength:

Answer:
d) -4.0
Explanation:
The magnification of a lens is given by

where
M is the magnification
q is the distance of the image from the lens
p is the distance of the object from the lens
In this problem, we have
p = 50 cm is the distance of the object from the lens
q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct
Also, q is positive since the image is real
So, the magnification is

Answer:
v=wavelength ×f
wavelength=v/f=455/655=0.694m