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faust18 [17]
2 years ago
15

The work function for magnesium is 3.70 ev. what is its cutoff frequency?

Physics
1 answer:
alexandr402 [8]2 years ago
7 0

The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.

<h3>What is cutoff frequency?</h3>

The work function is related to the frequency as

W0 = h x fo

where, fo = cutoff frequency and h is the Planck's constant

Given is the work function for magnesium is  3.70 eV.

fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴

fo = 8.93 x 10¹⁴ Hz.

Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.

Learn more about cutoff frequency.

brainly.com/question/14378802

#SPJ1

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Neporo4naja [7]

Answer:

C. tiny particles called charges flowing through the wires.

Explanation:

<h3> Hello!</h3>

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

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8 0
1 year ago
Read 2 more answers
A hoop of mass 2 kg, radius 0.5 m is rotating about its center with an angular speed of 3 rad's. A force of 10N is applied tange
Degger [83]

Answer:

The rotational kinetic energy of the hoop and the instantaneous change rate of the kinetic energy are 2.25 J and 15 J.

Explanation:

Given that,

Mass = 2 kg

Radius = 0.5 m

Angular speed = 3 rad/s

Force = 10 N

(I). We need to calculate the rotational kinetic energy

Using formula of kinetic energy

K.E =\dfrac{1}{2}\timesI\omega^2

K.E=\dfrac{1}{2}\times mr^2\times\omega^2

K.E=\dfrac{1}{2}\times2\times(0.5)^2\times(3)^2

K.E=2.25\ J

(II). We need to calculate the instantaneous change rate of the kinetic energy

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

On differentiating

\dfrac{K.E}{dt}=\dfrac{1}{2}m\times2v\times\dfrac{dv}{dt}

\dfrac{K.T}{dt}=mva....(I)

Using newton's second law

F = ma

a= \dfrac{F}{m}

a=\dfrac{10}{2}

a=5 m/s^2

Put the value of a in equation (I)

\dfrac{K.E}{dt}=mva

\dfrac{K.E}{dt}=mr\omega a

\dfrac{K.E}{dt}=2\times0.5\times3\times5

\dfrac{K.E}{dt}=15\ J/s

Hence, The rotational kinetic energy of the hoop and the instantaneous change rate of the kinetic energy are 2.25 J and 15 J.

3 0
3 years ago
What is another word that can be used to describe the position of the<br> object?
steposvetlana [31]

where the object is located

6 0
2 years ago
A person who weighs 509,45 N empties her lungs as much as
Masja [62]

Answer:

The weight of the girl = 1045.86 kg/m³

Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

⇒ D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

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<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

<em></em>

7 0
3 years ago
if you have several different substances mixed together, like Italian salad dressing, where do the most dense materials go where
Alecsey [184]
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Let me know if this helps! :)</span>
5 0
3 years ago
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