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faust18 [17]
1 year ago
15

The work function for magnesium is 3.70 ev. what is its cutoff frequency?

Physics
1 answer:
alexandr402 [8]1 year ago
7 0

The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.

<h3>What is cutoff frequency?</h3>

The work function is related to the frequency as

W0 = h x fo

where, fo = cutoff frequency and h is the Planck's constant

Given is the work function for magnesium is  3.70 eV.

fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴

fo = 8.93 x 10¹⁴ Hz.

Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.

Learn more about cutoff frequency.

brainly.com/question/14378802

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Answer:

All are true except the last point that says that a battery is a current source and the current at the outlet is always the same.

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2 years ago
An aluminum rod and a nickel rod are both 5.00 m long at 20.0 degree Celsius. The temperature of each is raised to 70.0 degrees
vitfil [10]

Answer:

0.002925 m

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Lt = LO(1 +α Δt ) here Lt is total length Lo is original length α is coefficient of linear expansion and Δt is change in temperature

<h2>for aluminium</h2>

α=25×10^-6

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Lt = 5(1+0.000665)

Lt =5.003325 m

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2 years ago
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Answer:

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2. v_{1f}=77.875m/s

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Explanation:

Use conservation of momentum:

p_i=p_f

m_1*v_{1i} + m_2*v_{2i} = m_1*v_{1f} + m_2*v_{2f}

1.

The expression for the magnitude of the BB's velocity is

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Answer:

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