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Lemur [1.5K]
3 years ago
11

En 50 gr de de agua se disuelven 10 gr de NaCl con una densidad de 1,08 m/cm3. Hallar la M y la m a. 3,06 M y 3,06m b. 3,06 M y

3,4 m c 3,4 M y 3,06 m d 3,5 M y 3,4 m
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

Opcion b. 3.06M y 3.4 m

Explanation:

Nuestra solución se compone de:

Soluto → NaCl (10 g)

Solvente → agua (50 g)

Primero, convertimos la masa de soluto a moles:

10 g . 1mol / 58.45g = 0.171 moles

Convertimos la masa de solvente, de g a kg → 50 g . 1kg/1000 g = 0.05 kg

m → molalidad (tipo de concentración que relaciona los moles de soluto en 1kg de solvente)

m = mol/kg → 0.171 mol/0.05kg = 3.42 m

Para calcular M, necesitamos el volumen de solución, y para eso aplicamos densidad. Antes, sumamos masa de soluto + masa de solvente, para obtener la masa de solución

50 g + 10 g = 60 g de solución

d = m /v → v = m /d → 60g / 1.08g/cm³ = 55.5 cm³

cm³ = mL

M = molaridad, la concentración que relaciona los moles de soluto en 1L de solución, pero que también podemos predecir como los milimoles de soluto en 1 mL de solución.

El volumen de solución está en mililitros → 55.5 mL

Convertimos moles a milimoles → 0.171 mol . 1000 mmol /mol = 171 mmol

M = 171 mmol /55.5 mL → 3.08 M

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While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°
Lana71 [14]

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

Solution:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

305 cal = 25 g ×0.210 cal/g.°C × T2 -  25°C

305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

7 0
3 years ago
If the initial temperature of a movable cylinder was 50 degrees Celsius
slega [8]

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

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Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

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Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

5 0
3 years ago
If a neutral compound is composed of carbon and hydrogen and you know that it has exactly 2 carbons connected by a double bond,
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Answer:

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