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Tamiku [17]
1 year ago
13

A. Would sucrase be classified as a oxidoreductase, a transferase, a lysase, an isomerase, a hydrolase, or a ligase enzyme? expl

ain your choice. B. Could sucrase be used to break down another disaccharide, such as lactose? explain your reasoning.
Chemistry
1 answer:
Hatshy [7]1 year ago
6 0

Sucrose, a disaccharide (consisting of two monosaccharides), is table sugar.

A digestive enzyme called sucrase catalyses the breakdown of sucrose into its component sugars, fructose and glucose. One type, sucrase-isomaltase, is secreted at the brush boundary of the small intestine. Invertase, a form of the sucrase enzyme that is more frequently found in plants, also hydrolyzes sucrose but does it in a different way.

<h3>What does sucrase break down into ?</h3>

Maltose is converted to glucose by maltase. Succrase and lactase, respectively, break down other disaccharides like sucrose and lactose. Sucrase and lactase are enzymes that break down sucrose (also known as "table sugar") and lactose (sometimes known as "milk sugar"), respectively, into glucose and fructose.

  • Both the breakdown of maltose into glucose and the breakdown of sucrose into glucose and fructose are carried out by the enzyme's sucrase subunit.

Learn more about Sucrase here:

brainly.com/question/910699

#SPJ4

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Suppose now that you wanted to determine the density of a small crystal to confirm that it is phosphorus. From the literature, y
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Answer:

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

Explanation:

Given that:

the density of the mixture = 1.82 g/mL

From the density of the pure samples

The density of CHCl_3 = 1.492 g/mL

The density of CHBr_3 = 2.890 g/mL

The total volume of the liquid mixture = 20.0 mL

Suppose the volume of  CHCl_3 = P ml

and the volume of CHBr_3 = Q ml

the sum of their volumes should be equal to the total volume of the mixture

P \ ml + Q \ ml = 20 ml  ----- (1)

However, we know that Density = mass/volume

∴ mass = density × volume

The equation can now be expressed as:

\mathtt{(Density \ of  \ CHCl_3 \times Vol. \ of  \ CHCl_3 ) + (Density  \  of \  CHBr_3  \times \ volume \ of \ CHBr_3)} = \mathtt{ (Density  \ of \ mixture \times volume \ of \ the \ mixture)}

1.492 g/mL × P mL + 2.890 g/mL × Q mL = 1.82 g/mL × 20 mL  ---- (2)

From equation (1) ;

let Q = 20 - P

The replace the value of P into equation (2)

1.492 g/mL × P mL + 2.890g/mL × (20 - P) mL = 1.82 g/mL × 20 mL

1.492 P g + 57.8g - 2.890 P g =  36.4g

1.492 P g - 2.890 P g = 36.4g - 57.8g

-1.398 P g = -21.4g

P = -21.4g/-1.398g

P = 15.31 mL

Q = 20 - P

Q = (20 - 15.31) mL

Q = 4.69 mL

∴

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

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Answer:

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