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Sphinxa [80]
3 years ago
6

Please help me with this

Physics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

a i. The higher curve is "thick wall" and the lower curve is "thin wall".

a ii. The thicker the wall, the more time it takes to transfer the same amount of heat. Thus, the thick wall would have a less steep drop in temperature as it transferred lesser heat from the room to the surroundings and the thinner wall would have a steeper drop in temperature as it conducted more heat away from the room to the surroundings.

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Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring consta
Zanzabum

Answer:

k_2=920\ N/m

Explanation:

Given that,

The spring constant of spring 1, k_1=230\ N/m

The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2, A_1=2A_2

As the magnitude of the maximum velocity is the same in each case, it means the maximum kinetic energy is same in each case. In other words, the total energy is same.

\dfrac{1}{2}k_1A_1^2=\dfrac{1}{2}k_2A_2^2

k_1A_1^2=k_2A_2^2

k_1(2A_2)^2=k_2A_2^2

k_2=920\ N/m

So, the spring constant of spring 2 is 920 N/m. Hence, this is the required solution.

3 0
3 years ago
Calculate the percentage increase in length of a wire of diameter 2.2 mm stretched by a load of
vesna_86 [32]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

8 0
3 years ago
A shell if fired from the ground with an initial velocity of 1,700 m/s at an initial angle of 55 degrees to the horizontal. Negl
Triss [41]

Answer:

Therefore the horizontal range = 294897.96 m.

Explanation:

Range of a projectile: The range is defined as the horizontal distance from the point of projection to the point where the projectile hit the projection plane again. The S.I unit of range is Meter (m).

It can be expressed mathematically as

R = u²sin2∅/g............................. Equation 1

Where R = Horizontal range, ∅ = angle of projection, u = initial velocity, g = acceleration due to gravity.

<em>Given: u = 1700 m/s, </em>∅ = 55°,

Constant: g = 9.8 m/s²

Substituting these values into equation 1

R = (1700²sin55)/9.8

R = 2890000/9.8

R = 294897.96 m.

Therefore the horizontal range = 294897.96 m.

8 0
3 years ago
What skills are used to move the body from one place to another? *
Anuta_ua [19.1K]
Your muscles, bones, heart and other things in the body.
8 0
3 years ago
Read 2 more answers
Unpolarized light passes through two polarizers. Find the fraction of light from the first polarizer that gets through the secon
meriva

Answer:

0.5

Explanation:

Data provided in the question:

The angle between their transmission axes, θ = 60°

Now,

We have the relation,

I₁ = I₀cos²θ

where,

I₁ is the intensity of the transmitted light

I₀ is the intensity of the incident light

on rearranging, we get

\frac{I_1}{I_0}=cos²60°

or

\frac{I_1}{I_0}=0.5

8 0
4 years ago
Read 2 more answers
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