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SVETLANKA909090 [29]
3 years ago
8

Need help with two physics questions!

Physics
1 answer:
nikitadnepr [17]3 years ago
8 0

1) The north component of the airplane velocity is 260 km/h.

2) The direction of the plane is 24^{\circ} north of east.

Explanation:

1)

In this problem, we have to resolve the velocity vector into its components.

Taking east as positive x-direction and north as positive y-direction, the components of the velocity along the two directions are given by:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the velocity

\theta is the angle between the direction of the velocity and the positive x-axis (the east direction)

For the airplane in this problem,

v = 750 km/h

\theta=20^{\circ}

So, the two components are

v_x = (750)(cos 20)=704.8 km/h

v_y = (750)(sin 20)=256.5 km/h

So, the component in the north direction is 256.5 km/h, so approximately 260 km/h.

2)

In this problem, we have to use vector addition.

In fact, the motion of the plane consists of two displacements:

- A first displacement of 220 km in the east direction

- A second displacement of 100 km in the north direction

Using the same convention of the same problem (x = east and y = north), we can write

d_x = 220 km

d_y = 100 km

Since the two vectors are perpendicular to each other, we can find their magnitude using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(220)^2+(100)^2}=241.7 km

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{100}{220})=24^{\circ} north of east.

Learn more about vectors here:

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

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