Answer:
1 Newton
Explanation:
F=9*10^9*q0q1/r^2]]
F=9*10^9*(q0q1)/ r^2
r=3cm
F=4N
F=9*10^9*(q0q1)/3^2
4=9*10^9*(q0q1)/9
4=10^9 q0q1
q0q1=4/10^9
q0q1=4*10^-9
To calculate the force between the forces at a distance of 6 cm
F=9*10^9*(q0q1)/ r^2
=9*10^9*(4*10^-9)/6^2
=9*10^9*(4*10^-9)/36
=10^9*4*10^-9/4
=10^9*10^-9
=1 Newton
Answer:
The correct option is: B that is 1/2 K
Explanation:
Given:
Two carts of different masses, same force were applied for same duration of time.
Mass of the lighter cart = 
Mass of the heavier cart = 
We have to find the relationship between their kinetic energy:
Let the KE of cart having mass m be "K".
and KE of cart having mass m be "K1".
As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.
Numerical analysis.
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Now,
Kinetic energies and their ratios in terms of momentum or impulse.
KE (K) of mass m.
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...equation (i)
KE (K1) of mass 2m.
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...equation (ii)
Lets divide K1 and K to find the relationship between the two carts's KE.
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The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.