2 years ago

What physical property is being measured in the image below?

Physics

1 answer:

charle [14.2K]2 years ago

7 0

The Liquid property

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Assuming the ball's initial velocity was 51 ∘ above the horizontal and ignoring air resistance, what did the initial speed of th

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horizontal distance of home run is 400 ft = 122 m

height of the home run is 3 ft = 0.9 m

now the angle of the hit is 51 degree

now we have equation of trajectory of the motion

$x = vcos\theta * t$

$y = v sin\theta * t - \frac{1}{2} gt^2$

solving above two equations we have

$y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}$

now here we will plug in all data

$0.9 = 122 tan51 - \frac{9.8 * 122^2}{2*v^2 * cos^251}$

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$\frac{184150.2}{v^2} = 149.75$

$v = 35.1 m/s$

<em>so the ball was hit with speed 35.1 m/s from the ground</em>

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