The circle will be dilated by a scale factor of 6.

What is AgNO3 + KCI-KNO3+AgCI. What type of reaction does this represent

PIT_PIT [208]

<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O

2C4H10 + 13 O2 ----> 8CO2 + 10H2O

1. Count the C on the left (4), put a 4 where the C on the right.

2. Count the H on the left (1), you have two on the right, so you multimply this two by 5. Put the 5 in front of the H2O

3. Count the O on the right. You have 4*2 + 5 = 13. You have two on the left, so you need 6.5 on the left.

4. Now multiply everything on the equation by two so you have nice integer numbers.

5. check you have the same amount of everything on each side.
Example C: left 8, right 8, etc.
I hope this helps. :)</span><span>
</span>

6 0

3 years ago

How does the jet stream influence weather?

LiRa [457]

Jets streams play a key role in determining the weather because they usually separate colder air and warmer air.

4 0

3 years ago

How many liters of fat would have to be removed to result in a 5.2 lb weight loss? The density of human fat is 0.94 g/mL?

aksik [14]

I don’t even know I’m just answering for pints

7 0

2 years ago

Convert 4.5 X 1022 molecules of H2O to moles.

noname [10]

Answer:

<h3>The answer is 0.075 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{4.5 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.074750830...$

We have the final answer as

<h3>0.075 moles</h3>

Hope this helps you

3 0

2 years ago

Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle

Sedaia [141]

Question in incomplete, complete question is:

Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle (electron) with a kinetic energy (Ek) of $4.71\times 10^{-15}J$ . What is the de Broglie wavelength of this electron (Ek = ½mv²)?