Answer: 0.100 m 
Explanation:
Elevation in boiling point is given by:

= Elevation in boiling point
i= vant hoff factor
= boiling point constant
m= molality
1. For 0.100 m 
, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be 
2. For 0.100 m 
, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be 
3. For 0.200 m 
, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 
4. For 0.060 m 
, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be 
Thus as concentration of solute is highest for
, the elevation in boiling point is highest and thus has the highest boiling point.
Answer:
a) 
b) 
Explanation:
Equation of reaction:

Initial pressure 3 1 0
Pressure change 2P 1P 2P
Total pressure = (3-2P) + (1-P) + (2P)
Total Pressure = 3.75 atm
(3-2P) + (1-P) + (2P) = 3.75
4 - P = 3.75
P = 4 - 3.75
P = 0.25 atm
Let us calculate the pressure of each of the components of the reaction:
Pressure of XO2 = 3 - 2P = 3 - 2(0.25)
Pressure of XO2 =2.5 atm
Pressure of O2 = 1 - P = 1 -0.25
Pressure of O2 = 0.75 atm
Pressure of XO3 = 2P = 2 * 0.25
Pressure of XO3 = 0.5 atm
From the reaction, equilibrium constant can be calculated using the formula:
![K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BPXO_%7B3%7D%5D%20%5E%7B2%7D%20%7D%7B%5BPXO_%7B2%7D%5D%20%5E%7B2%7D%5BPO_%7B2%7D%5D%20%7D)

Standard free energy:

b) value of k−1 at 27 °C, i.e. 300K



Also give you a 10, the last one looks really nice
“Esto quiere decir que en una lata de 330 ml tiene alrededor de 36 gramos de azúcar, mientras que una botella de 1 l tendrá 110 gramos”
110 gramos
Isotopes can represented in two ways. In the first way, the element's symbol is used with mass number at the upper left and atomic number written on the lower left of the symbol. In the other form of representation, the isotope name is written with a dash and mass number.
Given that the isotope has 92 protons. So the atomic number is 92.
The isotope has 143 neutrons
So the mass number = Total number of protons + Neutrons
= 92 + 143 = 235
Therefore, the two ways of representing the isotope is:
1. 
2. Uranium-235