Answer:
0.9612 g
Explanation:
First we <u>calculate how many moles are there in 3.00 g of CCl₃F</u>, using its <em>molar mass</em>:
- 3.00 g CCl₃F ÷ 137.37 g/mol = 0.0218 mol CCl₃F
Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, <em>the same amount of moles</em>.
Thus we <u>calculate how many grams would 0.0218 moles of N₂O weigh</u>, using the <em>molar mass of N₂O</em> :
- 0.0218 mol N₂O * 44.013 g/mol = 0.9612 g N₂O
<span>inorganic
Let's look at the choices and see why they work, or don't work.
monosaccharide
* Otherwise known as a simple sugar. And NaCl is definitely not a sugar of any type. So this is wrong.
disaccharide
* Complex sugar. And NaCl doesn't qualify either.
organic
* A definition of an organic compound is one that has carbon in it. NaCl has sodium and chlorine. No carbon at all, so this isn't the right answer. And I wish that organic was an earlier choice, since the sugars mentioned above are organic compounds.
inorganic
* This is the only possible choice. Salt is not an organic compound since it doesn't have carbon. So it can't be a sugar either. But it can and is inorganic.</span>
Answer:
east to west is the answer
Answer:
If 51.8 of Pb is reacting, it will require 4.00 g of O2
If 51.8 g of PbO is formed, it will require 3.47 g of O2.
Explanation:
Equation of the reaction:
2 Pb + O2 → 2 PbO
From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO
Molar mass of Pb = 207 g
Molar mass of O2 = 32 g
Molar mass of PbO = 207 + 32 = 239 g
Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO
= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO
Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.
If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2
