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2 years ago

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9. A container has 56 g of Sc and 95 g of Br 2 in it. If the reaction goes to completion, what is the maximum amount of ScBr3 wh

ich could be produced?

1 answer:

Talja [164]2 years ago

3 0

Answer:

c

Explanation:

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A solution contains 0.021 M Cl and 0.017 M I. A solution containing copper (I) ions is added to selectively precipitate one of t

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<u>Answer:</u> Copper (I) iodide will precipitate first.

<u>Explanation:</u>

We are given:

$K_{sp}$ of CuCl = $1.0\times 10^{-6}$

$K_{sp}$ of CuI = $5.1\times 10^{-12}$

Concentration of $Cl^-\text{ ion}=0.021M$

Concentration of $I^-\text{ ion}=0.017M$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

<u>For CuCl:</u>

$K_{sp}=[Cu^+][Cl^-]$

Putting values in above equation, we get:

$1.0\times 10^{-6}=[Cu^+]\times 0.021$

$[Cu^+]=\frac{1.0\times 10^{-6}}{0.021}=4.76\times 10^{-5}M$

Concentration of copper (I) ion = $4.76\times 10^{-5}M$

<u>For CuI:</u>

$K_{sp}=[Cu^+][I^-]$

Putting values in above equation, we get:

$5.1\times 10^{-12}=[Cu^+]\times 0.017$

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The Osmotic pressure can be obtained from the relationship;

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i = Vant Hoff factor = 1

C = concentration = ?

R = gas constant = 0.082 atmLK-1Mol

T = temperature = 20°c + 273 = 293 K

C = π/iRT

C = 0.037/1 * 0.082 * 293

C = 0.0015 M

Now;

Number of moles = C/V = 0.0015/100 * 10^-3

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Number of moles = mass/molar mass

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