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Morgarella [4.7K]
3 years ago
10

Somebody please....

Physics
2 answers:
mojhsa [17]3 years ago
7 0

Answer:

Wait what is the distance of the water from the br

Dmitry [639]3 years ago
6 0

Answer: 12 m/s

Explanation:

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What is the potential Energy?​
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brinliest plz

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3 years ago
The speed of a particle moving in a circle 2.0 m in radius increases at the constant rate of 4.4 m/s2. At an instant when the ma
Law Incorporation [45]

Answer:

The speed of the particle is 2.86 m/s

Explanation:

Given;

radius of the circular path, r = 2.0 m

tangential acceleration,  a_t = 4.4 m/s²

total magnitude of the acceleration, a = 6.0 m/s²

Total acceleration is the vector sum of  tangential acceleration and radial acceleration

a = \sqrt{a_c^2 + a_t^2}\\\\

where;

a_c is the radial acceleration

a = \sqrt{a_c^2 + a_t^2}\\\\a^2 = a_c^2 + a_t^2\\\\a_c^2 = a^2 -a_t^2\\\\a_c = \sqrt{a^2 -a_t^2}\\\\a_c = \sqrt{6.0^2 -4.4^2}\\\\a_c = \sqrt{16.64}\\\\a_c = 4.08 \ m/s^2

The radial acceleration relates to speed of particle in the following equations;

a_c = \frac{v^2}{r}

where;

v is the speed of the particle

v^2 = a_c r\\\\v= \sqrt{a_c r} \\\\v = \sqrt{4.08 *2}\\\\v = 2.86 \ m/s

Therefore, the speed of the particle is 2.86 m/s

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1.Un conductor este străbătut de un curent electric cu I = 1.
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