A ball is thrown upward from the ground with an initial speed of 22.0 m/s; at the same instant, another ball is dropped from a b
uilding 16 m high. after how long will the balls be at the same height
1 answer:
They will be together in 8 minutes
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The answer is ultraviolet rays
Answer:
V = a * t = 9.8 m/s^2 * 2.3 s = 22.5 m/s velocity after 2.3 s
S = 1/2 g t^2 since initial speed is zero
S = 1/2 * 9.8 m/s^2 * 5.29 s^2 = 25.9 m
The answer is d.
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The units of velocity is :
meter per second (m/s)
