1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Slav-nsk [51]
3 years ago
9

If an object is moving eastward and slowing down, then the direction of its acceleration is

Physics
1 answer:
Alchen [17]3 years ago
4 0
C. Eastward. Acceleration is the change in speed so it can be a positive (speeding up) or negative (slowing down) acceleration
You might be interested in
You use a 1200-watt hair dryer for 10 minutes each day. a. How many minutes do you use the hair dryer in a month? (Assume there
sertanlavr [38]
300 minuts
5 hours
1.2 killowatt
6 killowatt hour
6*0.15=0.9
$0.9

3 0
3 years ago
Suppose a baseball pitcher throws the ball to his catcher.
amm1812

a) Same

b) Same

c) Same

d) Throw the ball takes longer

e) F is larger when the ball is catched

Explanation:

a)

The change in speed of an object is given by:

\Delta v = |v-u|

where

u is the initial velocity of the object

v is the final velocity of the object

The change in speed is basically the magnitude of the change in velocity (because velocity is a vector, while speed is a scalar, so it has no direction).

In this problem:

- In situation 1 (pitcher throwing the ball), the initial velocity is

u = 0 (because the ball starts from rest)

while the final velocity is v, so the change in speed is

\Delta v=|v-0|=|v|

- In situation 2 (catcher receiving the ball), the initial velocity is now

u = v

while the final velocity is now zero (ball coming to rest), so the change in speed is

\Delta v =|0-v|=|-v|

Which means that the two situations have same change in speed.

b)

The change in momentum of an object is given by

\Delta p = m \Delta v

where

m is the mass of the object

\Delta v is the change in velocity

If we want to compare only the magnitude of the change in momentum of the object, then it is given by

|\Delta p|=m|\Delta v|

- In situation 1 (pitcher throwing the ball), the change in momentum is

\Delta p = m|\Delta v|=m|v|=mv

- In situation 2 (catcher receiving the ball), the change in momentum is

\Delta p = m\Delta v = m|-v|=mv

So, the magnitude of the change in momentum is the same (but the direction is opposite)

c)

The impulse exerted on an object is equal to the change in momentum of the object:

I=\Delta p

where

I is the impulse

\Delta p is the change in momentum

As we saw in part b), the change in momentum of the ball in the two situations is the same, therefore the impulse exerted on the ball will also be the same, in magnitude.

However, the direction will be opposite, as the change in momentum has opposite direction in the two situations.

d)

To compare the time of impact in the two situations, we have to look closer into them.

- When the ball is thrown, the hand "moves together" with the ball, from back to ahead in order to give it the necessary push. We can verify therefore that the time is longer in this case.

- When the ball is cacthed, the hand remains more or less "at rest", it  doesn't move much, so the collision lasts much less than the previous situation.

Therefore, we can say that the time of impact is longer when the ball is thrown, compared to when it is catched.

e)

The impulse exerted on an object can also be rewritten as the product between the force applied on the object and the time of impact:

I=F\Delta t

where

I is the impulse

F is the force applied

\Delta t is the time of impact

This can be rewritten as

F=\frac{I}{\Delta t}

In this problem, in the two situations,

- I (the impulse) is the same in both situations

- \Delta t when the ball is thrown is larger than when it is catched

Therefore, since F is inversely proportional to \Delta t, this means that the force is larger when the ball is catched.

6 0
4 years ago
At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety de
xxMikexx [17]

Answer:

  v₀ = 9,798 ft / s

Explanation:

We can solve this problem with kinematics in one dimension, when the train stops the speed is zero, the acceleration is negative so that the train stops. Let's use the equation

         v² = v₀² - 2 a d

         v = 0

         v₀ = √2 a d

In the problem it indicates that the acceleration is g / 2, we substitute

         v₀ = √2 (g / 2) d

Let's calculate

         v₀ = √ 2 32/2 3 = √32 3

         v₀ = 9,798 ft / s

8 0
4 years ago
What is the value of the angle of inclination of the slide?​
ruslelena [56]

Answer:

63°

that's my answer

but then I am sorry if I'm wrong

Explanation:

90-27 = 63°

7 0
3 years ago
HELP PLEASE DUE IN 3 MINUTES!!!! 60 POINTS
g100num [7]

Answer:

i think rocks towards is correct answer

7 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following is not a good reason to take lessons in a sport?
    11·2 answers
  • Which of the following exists around every object that has mass?
    7·2 answers
  • Huifen weighs herself on her bathroom scales.She says "My weight is 54 kg!"In Science, what Huifen said would be considered wron
    14·1 answer
  • Hey guys.. what’s 1,893,9379 x 0
    7·1 answer
  • A system of 18 electrons and 11 neutrons has a net charge of
    7·1 answer
  • 7 A steel sphere is released from a height
    12·1 answer
  • A 2 kg ball attached to a frictionless surface is being spun in a circle of radius 0.5 meters. The string will break when the te
    10·1 answer
  • 7) Se calcula dividiendo distancia entre tiempo
    12·1 answer
  • A large truck of mass 4M is traveling at a speed of V when it collides with a small car of mass M that is at rest. The truck and
    5·1 answer
  • A steel rod is initially very cold. If it is placed close to a fire, what happens?.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!