WILL GIVE BRAINLIEST , pls helppp .

Sergio [31]

Hi there!

In order to find x, we'll need to set up a proportion. This proportion is 77/22 = 87.5/x. Now, we need to cross-multiply, leaving us with 77x = 1925. Lastly, we'll need to divide in order to get the section that makes up the missing part of x. This is 25 ft. All that is left to do to find the total value of x is to add 25 and 22 together. The value of x is 47 feet.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

6 0

2 years ago

Need help with this. Hope someone can help

ratelena [41]

First, convert all of the cm measurements to m measurements (so they are all the same unit measurement)

2000 cm = 20 m 800 cm = 8m

Total Perimeter (Note that circumference of a semi-circle is 2 π r/2 = π r)

Add up the lengths of all of the outside edges. I am going to start on the top and move counter-clockwise:

40 + π (10) + 8 + 25 + 8 + (40 - 25 - 10) + 8 + 10 + 8 + π(10)

= 40 + 10π + 41 + (5) + 26 + 10π

= 112 + 20π

= 112 + 62.8

= 174.8

Answer: 174.8 m

Total Area

Split the picture into 5 sections (2 semi-circles, top rectangle, bottom left rectangle, and bottom right rectangle). Find the area for each of those sections and then add their areas together to find the total area.

2 semi-circles is 1 Circle: A = π · r² ⇒ A = π(20/2)² = π(10)² = 100π ≈ 314

top rectangle: A = L x w ⇒ A = 40 x 20 = 800

bottom left rectangle: A = L x w ⇒ A = 25 x 8 = 200

bottom right rectangle: A = L x w ⇒ A = 10 x 8 = 80

Total = 314 + 800 + 200 + 80 = 1394

Answer: 1394 m²

3 0

3 years ago

Please help been working on for 2 hours

alexandr1967 [171]

It’s best if you download Photomath

8 0

3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t

Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0

3 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

2 years ago