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2 years ago

Me podrían decir los nombres comunes de los siguientes hidrocarburos!! URGENTE AYUDA

Chemistry

2 answers:

blsea [12.9K]2 years ago

8 0

Answer:

No Se Espanol

Explanation:

Ilya [14]2 years ago

4 0

Answer:

fdhhdhdhdhhshdgdvdvebehbehdhehdhhddhdf

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In an experiment to determine how to make sulfur trioxide, a chemist combines 32.0 g of sulfur with 50.0 g of oxygen. She finds

LuckyWell [14K]

Answer:

The chemist needs to react 40 g of sulfur with 60 g of oxygen to make 100 g of sulfur trioxide.

Explanation:

2S (s) + 3O₂ (g) → 2SO₃ (g)

64g + 96g → 160 g

32g + 48g → 80 g

x + y → 100 g

1 mol SO₃ ___ 80g

n _______ 100g

n = 1.25 mol SO₃

1 mol S ___ 32 g

1,25 mol S __ 40 g

1 mol O₂ ___ 32 g

1,875 mol O₂ ___ 60 g

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3 years ago

If you hold a backpack in your hand, the force of gravity pulls it downward. What force keeps it from falling to the ground?

Deffense [45]

Answer:

The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.

Explanation:

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2 years ago

1) Which of the following is true about Earth’s plates?

tatyana61 [14]

Answer:

a because the others whould cause earthquakes

Explanation:

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2 years ago

Read 2 more answers

How can an object enter Earth's orbit?

pentagon [3]

When an object enters the Earth's atmosphere, it experiences a few forces, including gravity and drag. Gravity will naturally pull an object back to earth.

-Hope this helped, have a great day. ;)

3 0

2 years ago

Need to complete the chart

GalinKa [24]

Answer:

Row 1

$[H^+]=1.8\times 10^{-6}M$

$pH=-\log[H^+]=-\log[1.8\times 10^{-6}]=5.7$

pOh=14-pH=14-5.7=8.3

$pOH=-\log[OH^-]$

$[OH^-]=0.5\times 10^{-8}M$

Hence, acidic

Row 2

$[OH^-]=3.6\times 10^{-10}M$

$pOH=-\log[OH^-]=-\log[3.6\times 10^{-10}]=9.4$

pH=14-pOH=14 - 9.4 = 4.6

$pH=-\log[H^+]$

$[H^+]=2.6\times 10^{-5}M$

Hence, acidic

Row 3

pH = 8.15

$[H^+]=0.7\times 10^{-8}M$

pOH=14-pH=14 - 8.15 = 5.8

$pOH=-\log[OH^-]$

$[OH^-]=1.5\times 10^{-6}M$

Hence, basic

Row 4

pOH = 5.70

$[OH^-]=1.8\times 10^{-6}M$

pH=14-pOH=14 - 5.70 = 8.3

$pH=-\log[H^+]$

$[H^+]=0.5\times 10^{-8}M$

Hence, basic

3 0

3 years ago