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2 years ago

A 2.0-liter aqueous solution contains a total of 3.0 moles of dissolved NH4Cl at 25°C and standard pressure.

2 answers:

vladimir1956 [14]2 years ago

7 0

The molarity is a concentration unit which defined as the number of moles of solute divided by the number of liters of solution. So the molarity of the solution is 3/2=1.5 mol/L.

bija089 [108]2 years ago

3 0

Given that

Volume of solution = 2.0 L

Number of mole of solute = 3.0 mole

Therefore molarity = number of moles / volume in L

= 3.0 Mole /2.0 L

= 1.5 mole / L

= 1.5 M

Molarity:

The number of moles of solute per liter of solution is known as molarity of the solution. It symbolized by M. Molarity of any solution is a ratio of moles of solutes per liter of solution. It expressed by the following formula:

molarity = number of moles / volume in L

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The thermal stability of group 2 hydroxides increases down the group ? give reasons

VladimirAG [237]

ANSWERS:

Group 2 metal carbonates, nitrates and hydroxides decompose to heat to give the corresponding metal oxide and release CO2, NO2 and O2, and H2O respectively. The thermal stability increases down the group as theionic character of the compounds increases down the group.

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3 years ago

Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enou

swat32

39.96 g product form when 16.7 g of calcium metal completely reacts.

<h3>What is the stoichiometric process?</h3>

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

$Ca(s) + Cl_2(g)$ → $CaCl_2(s)$

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

$m_{ca_C_l_2}$ = 16.7 g Ca x $\frac{1 mol \;of \;Ca}{40g Ca}$ x $\frac{1 mol \;of \;CaCl_2}{1 mol \;Ca}$ x $\frac{111g of \;CaCl_2}{1 mol \;CaCl_2}$

$m_{ca_C_l_2}$ = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

Learn more about the stoichiometric process here:

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2 years ago

Which salt shows the least solubility change when the temperature is increased from 0 to 100 c?

Hunter-Best [27]

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Why are there more fossils of marine organism than of land organisms o dc

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Explanation:

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