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Archy [21]
3 years ago
9

Based on the information below, both Polaris and Sirius are much hotter than the Sun. However, on Earth, we feel the heat from t

he Sun and not from Polaris or Sirius because?
A.Earth’s seasons are caused by rotation around the Sun.
B.a year on the Sun is less than a year on Polaris or Sirius.
C.Polaris and Sirius are farther north than the Sun.
D.Polaris and Sirius are farther away than the Sun.
Chemistry
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

<h2> <u>D</u><u>.</u><u> </u><u>Polaris</u><u> </u><u>and</u><u> </u><u>Sirius</u><u> </u><u>are</u><u> </u><u>farther</u><u> </u><u>away</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>Sun</u><u>.</u></h2>

Explanation:

  • <em>T</em><em>h</em><em>a</em><em>t</em><em>'</em><em>s</em><em> </em><em>w</em><em>h</em><em>y</em><em> </em><em>w</em><em>e</em><em> </em><em>c</em><em>a</em><em>n</em><em> </em><em>f</em><em>e</em><em>e</em><em>l</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>h</em><em>e</em><em>a</em><em>t</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>t</em><em>h</em><em> </em><em>S</em><em>u</em><em>n</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>n</em><em>o</em><em>t</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>P</em><em>o</em><em>l</em><em>a</em><em>r</em><em>i</em><em>s</em><em> </em><em>o</em><em>r</em><em> </em><em>S</em><em>i</em><em>r</em><em>i</em><em>u</em><em>s</em><em>.</em>
azamat3 years ago
7 0

Answer:

  D.  Polaris and Sirius are farther away than the Sun.

Explanation:

The radiation intercepted by Earth is inversely proportional to the square of the distance from the source. Polaris and Sirius are substantially farther away than the sun.

Polaris, for example, is about 27 million times farther away, so even though it is 4000 times brighter, we receive on the order of 5×10^-12 as much radiation from that star as from the sun.

We feel less heat from stars other than the Sun because they are farther away.

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4 years ago
How long does it take electrons to get from the car battery to the starting motor? Assume the current is 137 A and the electrons
WARRIOR [948]

Answer:

t = 55.79 min

Explanation:

First, the problem is asking for calculate the time that it takes electrons from the battery to the motor.

The general formula to calculate time is:

<em>t = d/V (1)</em>

Where:

d: distance or length

V: speed

Now, we don't have data of speed, but we can know an expression of current density in function of the distance which is the following:

<em>J = n*q*V (2)</em>

Where:

q: charge of the particle (1.6x10^-19 C)

n: number of charge carriers per unit of volume

Current density (J) is actually current per Area so:

<em>J = I/A (3)</em>

Replacing (3) in (2) we have:

I/A = nqV

Solving for V:

<em>V = I/Anq (4)</em>

Finally, if we replace this expression in (1) we have:

<em>t = nqAd / I (5)</em>

Now, the value of n, it's not given but it can be calculated because we have mass density, molar mass and avogadro's number, so this value of "n" can be calculated using the following expression:

<em>n = D * Av / MM (6)</em>

Where:

D: mass density (kg/m³)

Av: avogadro number (6.02x10^23 atom/mol)

MM: molar mass (kg/mol)

Putting the data that we know to calculate n we have:

n = 8960 * 6.02x10^23 / 0.0635

n = 8.49x10^28 atom/m³

Now with the value of n, we can finally calculate the time:

<em>t = nqAd / I </em>

A is the area and it should be in m²: 44.6 mm² / 1x10^6 m = 4.46x10^-5 m²

d is the length in meter: 75.7 cm / 100 cm/m = 0.757 m

so replacing these data in (5):

t = 8.49x10^28 * 1.6x10^-19 * 4.46x10^-5 * 0.757 / 137

t = 3,347.63 s

But the answer is in minute so:

t = 3,347.63 / 60

<em>t = 55.79 min</em>

so the electrons takes 56 min aprox. to go from the car battery to the starting motor.

4 0
3 years ago
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