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What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026

vesna_86 [32]

Answer : The mass of silver chlorate will be 2.654 grams.

Explanation :

The balanced chemical reaction is,

$2AgClO_3\rightarrow 2AgCl+3O_2$

First we have to calculate the moles of oxygen gas at STP.

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

So, 0.466 L volume of oxygen gas present in $\frac{0.466}{22.4}=0.0208$ mole of oxygen gas

Now we have to calculate the moles of silver chlorate.

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from $\frac{2}{3}\times 0.0208=0.01387$ moles of silver chlorate

Now we have to calculate the mass of silver chlorate.

$\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3$

Molar mass of silver chlorate = 191.32 g/mole

$\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g$

Therefore, the mass of silver chlorate will be 2.654 grams.

3 0

3 years ago

is it true that in a solution the tiny pieces of one substance are spread equally through the other substance

ziro4ka [17]

Yes this is true otherwise it would not be a solution

3 0

3 years ago

How a cold front affects weather.

miskamm [114]

Answer:

A cold front forms when a cold air mass pushes into a warmer air mass. Cold fronts can produce dramatic changes in the weather. ... As the cold front passes, winds become gusty. There is a sudden drop in temperature, and also heavy rain, sometimes with hail, thunder, and lightning.

4 0

3 years ago

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A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius

Nonamiya [84]

Data Given:
Pressure = P = ?

Volume = V = 3.0 L

Temperature = T = 115 °C + 273 = 388 K

Mass = m = 75.0 g

M.mass = M = 44 g/mol

Solution:
Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
P V = n R T
Solving for P,
P = n R T / V ------ (1)
Calculating Moles,
n = m / M

n = 75.0 g / 44 g.mol⁻¹

n = 1.704 mol

Putting Values in Eq. 1,

P = (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

P = 18.08 atm

7 0

3 years ago

As the [H+] in a solution decreases, what happens to the [OH–]? A. It increases and the pH increases. B. It increases and the pH

AleksAgata [21]

<h3><u>Answer;</u></h3>

D. It decreases and the pH increases.

<h3><u>Explanation;</u></h3>

pH is a measure of the hydorgen ion concentration of a solution. Solutions with a high concentration of hydrogen ions have a low pH and solutions with a low concentrations of H+ ions have a high pH.
<em><u>[H+] and [OH-] are inversely related. Therefore; As the concentration of H+ increases the pH decreases. Since the concentrations of H+ and OH- are inversely proportional, as one goes up, the other goes down. </u></em>
<em><u>Therefore, an increase in OH- concentration will correspond to an increase in pH and a decrease in the concentration of H+.</u></em>

5 0

3 years ago

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