Answer:
newtons 3rd law
Explanation:
if the engine is supplying propulsion, then the mass will be pushed by it.
You can use the HWE (Hardy Weinberg Equilibrium) equations :
p + q = 1
p^2 + 2pq + q^2 = 1
If the allele combinations do not equal one after a while, evolution has occurred.
<span>moles glucose = 19 g / 180 g/mol= 0.105
M = 0.105 / 0.100 L = 1.05
moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216
New concentration = 0.0216 /0.500 L = 0.0432 M
moles in 100 mL = 0.100 L x 0.0432 = 0.00432
mass = 0.00432 x 180 g/mol= 0.778 g</span>
Explanation:
but.......you havent attached a picture?
<u>A. reaction A: chemical; reaction B: nuclear</u>
Answer:
Solution given:
as
Circle 2: Reaction B
-Involves neutrons
-Happens inside atomic nucleus
-Releases relatively large amounts of energy
<u>I</u><u>t</u><u> </u><u>h</u><u>a</u><u>p</u><u>p</u><u>e</u><u>n</u><u>s</u><u> </u><u>o</u><u>n</u><u> </u><u>n</u><u>o</u><u>r</u><u>m</u><u>a</u><u>l</u><u> </u><u>c</u><u>h</u><u>e</u><u>m</u><u>i</u><u>c</u><u>a</u><u>l</u><u> </u><u>reaction</u><u>.</u>
Circle 2: Reaction B
-Involves neutrons
-Happens inside atomic nucleus
-Releases relatively large amounts of energy
<u>I</u><u>t</u><u> </u><u>h</u><u>a</u><u>p</u><u>p</u><u>e</u><u>n</u><u>s</u><u> </u><u>o</u><u>n</u><u> </u><u>n</u><u>u</u><u>c</u><u>l</u><u>e</u><u>a</u><u>r</u><u> </u><u>r</u><u>e</u><u>a</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u>.</u>