-- She went up for 0.4 sec and down for 0.4 sec.
-- The vertical distance traveled in gravity during ' t ' seconds is
D = (1/2) x (g) x (t)²
= (1/2) (9.8 m/s²) (0.4 sec)²
= (4.9 m/s²) x (0.16 s²)
= 0.784 meter ( B )
According to my assumptions,the answer closest to the perfection is :
c. they show royalty instead of peasants.
To solve this problem we will apply the concepts related to the work theorem for which it is defined as the product of Force and distance. In turn, we will use the energy conservation theorem for which the applied work must be equivalent to the total kinetic energy on the body.
The work is defined as

Here,
F = Force
d = Displacement
Replacing with our values we have that


Now by conservation of energy,



Solving for v,


Therefore the correct answer is D.
Power is defined by the rate of work done by the object. Statement D represents the correct definition of Power.
<h3>What is Power?</h3>
Power can be defined as the transfer of energy from one place to another place. The rate at which this energy is transferred is called power.
In other words, the rate at which the work is done by an object is called its power. The mathematical representation of power is given as,

Here, P is the power,
is the change in energy or work done and
change in time.
The Power can be written in SI units as Watt or J/s.
Hence we can conclude that the power is the rate at which work is accomplished. Statement D is the correct representation of Power.
To know more about power, follow the link given below.
brainly.com/question/1618040.
Answer:
a) The charge of the capacitor is 4.25x10⁻¹¹C
b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.
c) The potential difference across the plates is 18 V
d) The work is 7.64x10⁻¹⁰J
Explanation:
The capacitance of the capacitor is equal to:

A = 2 cm² = 0.0002 m²
d = 0.5 mm = 0.0005 m
Replacing:

a) The charge of the capacitor is equal to:
Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C
b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)
c) If distance is increased, we have:

The potential is:

d) The work done is equal to:
