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3 years ago

FeO+ PdF2 ---> FeF2+PdO balance please worth 50 points

Chemistry

2 answers:

ICE Princess25 [194]3 years ago

5 0

Answer:

This is not worth 50 points liar

Explanation:

rosijanka [135]3 years ago

4 0

Answer: FeO

Explanation:

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Please help ASAP!!

joja [24]

Answer:

The pond has more energy because I is so much larger that the Cup of boiling water. Since that mass of the pond is so much larger, It is generating more energy than a boiling cup of water.

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3 years ago

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A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of

andrew-mc [135]

Answer: The molecular formula for the given organic compound X is $C_6H_{8}O_7$

Explanation:

We are given:

Mass of $CO_2=4.13g$

Mass of $H_2O=1.13g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, = $\frac{12}{44}\times 4.13=1.13g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, $\frac{2}{18}\times 1.13=0.125g$ of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = $\frac{0.094}{0.094}=1$

For Hydrogen = $\frac{0.125}{0.094}=1.33$

For Oxygen = $\frac{0.109}{0.094}=1.16$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is $C_6H_8O_7$

Empirical mass = $6\times 12+8\times 1+7\times 16=192g$

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

Putting values in above equation, we get:

$n=\frac{192g/mol}{192g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_6H_8O_7\times 1=C_6H_{8}O_7$

Thus molecular formula for the given organic compound X is $C_6H_{8}O_7$

7 0

3 years ago

You are given a small bar of an unknown metal. You find the density of the metal to be 10.5 g/cm3. An X-ray diffraction experime

Artemon [7]

Answer:

Explanation:

5 0

4 years ago

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A liquid with a high viscosity cannot be a mixture.

enot [183]

It can be made true by changing "cannot" to "can".

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3 years ago

Which of the following weathering processes involves the constant freezing and thawing of water?

Artemon [7]

Frost wedging

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Some agents of weathering are wind, water, glacier and gravity.

In physical weathering, rocks are broken down mechanically into smaller bit.
Freezing and thawing allows for the propagation of physical weathering.
Water within cracks will expand when they freeze significantly.
This will further expand and widen the cracks.
When the ice thaws the stress is relieved.
When the process continues on and on over the year, a rock will eventually break down.
This is common around the temperate and polar regions.

Learn more:

weathering brainly.com/question/876569

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4 0

3 years ago