Answer:25.61 m/s
Explanation:
Given
truck is moving eastbound with a velocity of 16 m/s
Velocity of truck 
SUV is moving south with a velocity of 20 m/s
Velocity of SUV in vector form 
Velocity of truck relative to the SUV


Magnitude of relative velocity is

The dependent variable in this experiment is the mass of each liquid.
Density is the ratio of mass to volume of a substance. In this experiment, since the volume of each liquid is given, to get density, mass of each quantity must be known which is the outcome.
Density also depend on the mass of a substance and density can easily be identified by mass if all the substance in question have the same volume.
In this experiment, all the liquid have the same volume. Since the student want to list them in order from the least dense to the most dense, how dense the liquid are will be a function of the differences in liquid mass.
The least dense liquid will float. That is, will be at the top most of the container. While the most dense will be at the bottom of the container.
Therefore, the dependent variable in this experiment is the mass of each liquid
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The destructive interference formula for diffraction grating problems is
.
<h3>What is the definition of destructive interference?</h3>
Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.
The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by
.
The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.
Hence the destructive interference formula for diffraction grating problems is
.
To learn more about destructive interference refer to the link;
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Answer:
a = -04978 m / s²
Explanation:
For this exercise we can use the kinematics equations, as the initial speed, distance and time indicate, we can use
x = x₀ + v₀ t + 1 /2 a t²
½ a t² = x-x₀ - v₀ t
a = (x-x₀ - v₀ t) 2 / t²
let's reduce the magnitudes to the SI system
x₀ = 1000 mm = 1 m
x = 5000mm = 5m
let's calculate
a = (5 - 1 - 15 60) 2/60²
a = -04978 m / s²
negative sign indicates that braking is related