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Alexandra [31]
3 years ago
5

“Space School”

Physics
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

Space School is the incredible story of how astronauts train underwater to live and work in space. From micro-gravity simulation at NASA's Neutral Buoyancy Lab, to living under the sea at Aquarius Reef Base, astronauts spend a lot of time training underwater.

Explanation:

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The combination of all forces that act on an object are (2 points)
qaws [65]

Answer:

A) The net force

Explanation:

If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement.

5 0
4 years ago
An athlete runs around a circular track of radius 50 m and finishes at the same point where he began his journey. His total disp
son4ous [18]

Answer:

Explanation:

His displacement is 0 because he ended up exactly where he started.

5 0
3 years ago
A 10 lb. cat needs 31⁄2 tablets that each contain 6 mg of a drug. what's the equivalent dose in mg/kg?
mina [271]

Mass of cat = 10 lb

1 lb = 0.454 kg

So mass of cat is 4.54 kg

Number of tablets given to cat

N = 3\frac{1}{2}

Each tablet has 6 mg of drug

Total drug given to cat

Drug = 3\frac{1}{2} * 6mg

Drug = 21 mg

Now dose given to cat in mg/kg form

Dose = \frac{mass of drug in mg}{mass of cat in kg}

Dose = \frac{21mg}{4.54kg}

Dose = 4.63mg/kg

4 0
4 years ago
A fireman is standing on top of a building 19 m high, holding a firehose 1 m above the top of the building. She finds that if sh
DENIUS [597]

Answer:

A 2 d vector model

The acceleration function is -9.8 m/s2 which is gravity

Initial velocity on the Y axis is 0, on the X axis is 12 m/s

Inital position is 20 mts above the ground.

It takes the water 1.01 seconds to reach the other building.

THe distace from one building to the other is 12.11 meters.

Explanation:

In order to solve this you just need to carefully read the problem and the data you are given, and use the formula for height in free fall:

h=\frac{1}{2} g*t^{2}

So first the data, we know that the water is coming out at a height of 20 meters since the building is 19 meters tall and the fireman is holding the firehose 1 meter above it, and the water is hitting the second building at a height of 15 meters, that means that the water is travelin -5meters.

Gravity as it doesn´t say otherwise would be 9.8m/s2 since that is gravity on earth, and water is leaving the firehose at 12m/s horizontally.

We can calculate the time by using the height formula fro free fall:

h=\frac{1}{2} g*t^{2}\\5=\frac{1}{2} 9.81*t^{2}\\t^{2}= \frac{10}{9.8} \\t^{2}=1.0193\\t=1.009 seconds

So it takes 1.009 seconds for the water to frop from 20 to 15 meters, as the horizontal velocity remains the same we just multiply it by the time and we get the horizontal distance between the two buildings and that would be:

12.11 meters.

5 0
4 years ago
A 0.31 kg cart on a horizontal frictionless track is attached to a string. The string passes over a disk-shaped pulley of mass 0
Stella [2.4K]

To solve this problem it is necessary to apply the concepts related to Newton's second law and its derived expressions for angular and linear movements.

Our values are given by,

M_{cart} = 0.31kg\\m_{pulley} = 0.08kg\\r_{pulley} = 0.012m\\F = 1.1N\\

If we carry out summation of Torques on the pulley we will have to,

F_2*d-F_1*d = I \alpha

Where,

I = Inertia moment

\alpha =Angular acceleration, which is equal in linear terms to a/r (acceleration and radius)

The moment of inertia for this object is given as

I = \frac{1}{2} mr^2

Replacing this equations we have know that

(F_2 - F_1)d = (\frac{1}{2}(m_{pulley})r^2) (\frac{a}{r})

F_2 - F_1 = \frac{1}{2}m_{pulley} \frac{F_1}{M_{cart}}

F_2 = (1+\frac{1}{2}(\frac{m_{pulley}}{M_{cart}}))F_1

Or

F_1 = \frac{F_2}{(1+\frac{1}{2}(\frac{m_{pulley}}{M_{cart}}))}

Replacing our values we have that

F_1 = \frac{1.1}{(1 + (0.5)(\frac{0.08}{0.31}))}

F_1 = 0.974 N

Therefore the tension in the string between the pulley and the cart is  0.974 N

6 0
4 years ago
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