Answer:
The volume is
<h2>180 mL</h2>
Explanation:
In order to solve for the volume we use the formula for Boyle's law which is
<h3>
</h3>
where
P1 is the initial pressure
V1 is the initial volume
P2 is the final pressure
V2 is the final volume
Since we are finding the final volume we are finding V2
Making V2 the subject we have
<h3>
</h3>
From the question
P1 = 300 mmHg
V1 = 300 mL
P2 = 500 mmHg
Substitute the values into the above formula and solve for the final volume obtained
That's
<h3>
</h3>
We have the final answer as
<h3>180 mL</h3>
Hope this helps you
Thank you for posting your question here brainly. Based on the problem mentioned above the largest mass that water molecule could have using other isotopes is <span>24 amu. Below is the solution, I hope the answers helps.
</span><span>T2_18O = 24</span>
2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)
The molar ratio between NaCN : HCN is 2:2 or 1:1
Mass of HCN = 16.7 g
Molar mass of HCN = 1 + 12 + 14 = 27 g/mol
Molar mass of NaCN = 49 g/mol
Therefore, the mass of NaCN is
16.7 g of HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN
Therefore, 30.3 grams of NaCN gives the lethal dose in the room.
You have to figure out a way to write the two unknown abundances in terms of one variable.
The total abundance is 1 (or 100%). So if you say the abundance for the first one is X then the abundance for the second one has to be 1-X (where X is the decimal of the percentage so say 0.8 for 80%).
203(X) + 205(1-X) = 204.4
Then you just solve for X to get the percentage for TI-203.
And then solve for 1-X to get the percentage for TI-205.
After that the higher percentage would be the most abundant.
203x + 205 - 205x = 204.4
-2x + 205 = 204.4
-2x = -0.6
x = 0.3
1-x = 0.7
Then the TI-205 would have the highest percentage and would be the most abundant.
