The pH of the solution of the given acid is 3.099
Let HX be the weak acid:
HX ⇌ 
+ 
For which:
= [ ][ ] / [HX]
If lies in the range 
we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.
Rearranging and taking negative logs of both sides gives:
pH = ![\frac{1}{2} [pK_{a} - loga]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5BpK_%7Ba%7D%20-%20loga%5D)
a is the concentration of the acid.
= -log (2×
) = 5.69
pH = ![\frac{1}{2} [5.69- (-0.508)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5B5.69-%20%28-0.508%29%5D)
pH = 3.099
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The evidence that a chemical reaction occurred is can be change in color , formation of a precipitate , Here in the case when 6 m HCl to the solution of sodium acetylsalicylate, the formation of precipitate that is of aspirin takes places that can be taken as a evidence that a reaction is occured. The reaction can be seen in the image attached.
Answer:
Oxide of manganese, Potassium permanganate, Manganese bromide and manganese oxide.
Explanation:
1. Manganese dioxide
Its chemical formula is 
. It is +4 oxidation state. It is a black solid which is fairly stable.
2. Potassium permanganate
Its chemical formula is 
. It is commonly used in the laboratories as oxidizing agent. They appear black in color.
3 Manganese bromide
Its chemical formula is 
4. Oxides of manganese
Chemical formula is 
The most stable state of Manganese is +2 oxidation state.
<span>Water has a high specific heat. ...Water in a pure state has a neutral pH. ...Water conducts heat more easily than any liquid except mercury. ...Water molecules exist in liquid form over an important range of temperature from 0 - 100° Celsius. ...<span>Water is a universal solvent.</span></span>
Answer:
c. I, II and III
Explanation:
The cell is as follows
Cr / Cr⁺²(1M) // H⁺ ( 1 M ) / H₂
Standard reduction potential of hydrogen cell is zero . Standard reduction potential is negative E for Cr⁺² / Cr(1M) half cell
Cell potential = Ecathode - Eanode
= 0 - ( - E)
= E
E is cell potential and also standard cell potential or emf of the cell .
Standard reduction potential that is for Cr3+/Cr. is - E .
Hence statement I , II , III are right . IV th statement is wrong because of sign
Option c is correct.
