Ask question

Ask question

All categories

2 years ago

14

A 240V single phase 6000 W heavy duty commercial electric heater runs constantly for 36 hours. If electricity cost $0.13/kWh, ho

w much does it cost to run the heater?
a. $28
b. $0.78
c. $18.72
d. $7.80

2 answers:

Aloiza [94]2 years ago

5 0

Answer:

A. $28

Explanation:

We have the load to be 240V

6000W will be converted to kilowatts

6000/1000 = 6kW

Time heater runs for 36 hours

Cost of electricity = $0.13/Kwh

The question needs us to find cost of running this electric heater

Total kilowatts

= 6kw x 36 hours

= 216kwh

Then the total cost = 216 x $0.13

= 28.08

= $28

Anon25 [30]2 years ago

4 0

Ccccccccccccccccccccc

You might be interested in

PELASEE HELPPP WITH MARK BRAINLIST!!!! You are stopped at a red light, and a long string of cars is crossing in front of you. Wh

choli [55]

Answer:

1st one.

Explanation:

I think that because they the one who is going to get a ticket and also you will not gonna get in a car accident.

7 0

3 years ago

Read 2 more answers

Techm digital definition comprises of

KonstantinChe [14]

Answer:

Below is the response to the given question:

Explanation:

The relevant services supplied through TechMahindra Digital Services Provider are among the different options given in n inquiry. This is a digital company that has offered its customers an end-to-end solution that digitalizes all the requirements for client operations. It offers digital solutions, services cloud-based, digital marketing strategies, and then all client needs.

8 0

2 years ago

what is the transfer function of the loaded filter? express your answer in terms of the variables r , l , rl , and s .

NISA [10]

Loaded, $H_{Loaded}$ (s) = $\frac{RR_{L} }{R+R_{L} } /(\frac{RR_{L} }{R+R_{L} }+SL)$ = $\frac{RR_{L}/L }{R+R_{L} } /(\frac{RR_{L} /L}{R+R_{L} }+S)$ is the loaded filter's transfer function.

A graded filter that, by virtue of its weight and permeability, stabilises the foot of an earth dam or other construction when it is installed at the base of that structure.

Air filters with depth loaded are made to achieve precisely that. They add particles gradually to create air passageways, reducing constriction. You may save time and money by using filters that last longer thanks to them. The bigger particles are caught at the filter's beginning, while the smaller particles are caught as it gets closer. This is intended to avoid rapid surface loading, hence facilitating more airflow. This enables longer-lasting filtration as well.

On the other hand, surface loading filters catch every particle that is on its surface. No matter how big or little the particles are, it doesn't care.

Learn more about Loaded here:

brainly.com/question/20039214

#SPJ4

3 0

1 year ago

zener shunt regulator employs a 9.1-V zener diode for which VZ = 9.1 V at IZ = 9 mA, with rz = 40 and IZK= 0.5 mA. The available

gulaghasi [49]

Answer:

$V_z=9.1v$

$V_{zo}=8.74V$

$I=10mA$

$R=589 ohms$

Explanation:

From the question we are told that:

Zener diode Voltage $V_z=9.1-V$

Zener diode Current $I_z=9 .A$

Note

$rz = 40\\\\IZK= 0.5 mA$

Supply Voltage $V_s=15$

Reduction Percentage $P_r= 50 \%$

Generally the equation for Kirchhoff's Voltage Law is mathematically given by

$V_z=V_{zo}+I_zr_z$

$9.1=V_{z0}+9*10^{-3}(40)$

$V_{zo}=8.74V$

Therefore

$At I_z-10mA$

$V_z=V_{z0}+I_zr_z$

$V_z=8.74+(10*10^{-3}) (40)$

$V_z=9.1v$

Generally the equation for Kirchhoff's Current Law is mathematically given by

$-I+I_z+I_l=0$

$I=10mA+\frac{V_z}{R_l}$

$I=10mA+\frac{9.1}{0}$

$I=10mA$

Therefore

$R=\frac{15V-V_z}{I}$

$R=\frac{15-9.1}{10*10^{-3}}$

$R=589 ohms$

5 0

3 years ago

*13–52. A girl, having a mass of 15 kg, sits motionless relative to the surface of a horizontal platform at a distance of r = 5

Dennis_Churaev [7]

Answer:

w = 0.626 rad / s, v = 3.13 m/s

Explanation:

For this exercise let's use Newton's second law

F = m a

Where the force is a friction force and the acceleration is centripetal,

a = v² / r = w² r

The formula for friction force

fr = μ N

In a free body diagram

N- W = 0

W = N

The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace

μ m g = m w² r

w = √ μ g / r

Let's calculate

w = √(0.2 9.8 / 5)

w = 0.626 rad / s

angular and linear velocity are related

v = w r

v = 0.626 5

v = 3.13 m/s

6 0

3 years ago