Answer:
581 Joules.
Explanation:
Using the formula;
Q = m × c × ∆T
Where;
Q = amount of heat absorbed (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to the information provided in this question;
Q = ?
mass of ice = 15.9g
initial temperature = -4°C
final temperature = 14°C
Hence, ∆T = 14 - (-4) = 14 + 4 = 18°C
specific heat capacity (c) of ice in J/g°C = 2.03 J/g°C
Using Q = m × c × ∆T
Q = 15.9 × 2.03 × 18
Q = 32 × 18
Q = 581 Joules.
