Question

Calculate the amount of heat energy required to heat up 15.9 grams of ice from -4 °C to 14°C.

Answer 1

Answer:

581 Joules.

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the information provided in this question;

Q = ?

mass of ice = 15.9g

initial temperature = -4°C

final temperature = 14°C

Hence, ∆T = 14 - (-4) = 14 + 4 = 18°C

specific heat capacity (c) of ice in J/g°C = 2.03 J/g°C

Using Q = m × c × ∆T

Q = 15.9 × 2.03 × 18

Q = 32 × 18

Q = 581 Joules.