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3 years ago

How can magnets cause objects to have kinetic energy?

Physics

2 answers:

yanalaym [24]3 years ago

7 0

Answer

The only thing I can come up with is if you used it to pull it either on a flat surface or down a hill.

Explanation:

I don't %100 know so if I'm wrong sorry

Zanzabum3 years ago

4 0

Answer:

If there is a system of magnets being held in place, there is potential energy. When you let go the potential energy makes to kinetic energy and the magnets move.

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hjlf

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3 years ago

a doghouse has a mass of 98 kg, and the coefficient of friction between it and the ground is 0.95. what is the maximum force of

MaRussiya [10]

The maximum force of friction:

F = μ* N, where μ is the friction coefficient and N id the force of the doghouse normal to the surface.

N for a flat surface would be: N = m*g, where m is the mass and g is the gravitational acceleration = 9,81 m/s².

Combined:

F = μ * g * m

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4 years ago

Read 2 more answers

HELP!!

Maru [420]

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3 years ago

Cuộn dây có N = 1000 vòng, mỗi vòng có diện tích S = 20 cm2 đặt trong một từ trường đều. Trục của cuộn dây song song với vectơ c

yanalaym [24]

Sorry i don’t understand would love to help tho !

7 0

3 years ago

Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential

mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0

3 years ago