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KatRina [158]
3 years ago
14

A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on th

e same track at a speed of 1 m/s. They collide and stick together! What is the final momentum of the new combined train?
A. 100 kgm/s
B. 600 kgm/s
C. 800 kgm/s
D. 80 kgm/s
Physics
1 answer:
Art [367]3 years ago
6 0

Answer:

Let the momentum of the orange train be positive

P = 100 * 8 - 200 * 1 = 600 kg-m/s

P(final) = 600 kg-m/s

P / M = 600 kg-m/sec / 300 kg = 2 m/s    

Answer-B     final momentum = 600 kg-m/s

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Diano4ka-milaya [45]

Answer:

yes

Explanation:

The solubility of glucose at 30°C is

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4 0
3 years ago
What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)
puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

3 0
3 years ago
DEFINE HEAT CAPACITY
Rudiy27
The number of heat units needed to raise the temperature of a body by one degree.
4 0
3 years ago
Read 2 more answers
The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is
Kazeer [188]
The electrical force acting on a charge q immersed in an electric field is equal to
F=qE
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C
5 0
3 years ago
Steam enters a one-inlet, two-exit control volume at location (1) at 360°C, 100 bar, with a mass flow rate of 2 kg/s. The inlet
yaroslaw [1]

Answer:

The inlet velocity is 21.9 m/s.

The mass flow rate at reach exit is 1.7 kg/s.

Explanation:

Given that,

Mass flow rate = 2 kg/s

Diameter of inlet pipe = 5.2 cm

Fifteen percent of the flow leaves through location (2)  and the remainder leaves at (3)

The mass flow rate is

m_{2}=0.15\times2

We need to calculate the mass flow rate at reach exit

Using formula of mass

m_{3}=m_{1}-m_{2}

m_{3}=2-0.15\times2

m_{3}=1.7\ kg/s

We need to calculate the inlet velocity

Using formula of velocity

v=\dfrac{m}{\rho A}

Put the value into the formula

v=\dfrac{2}{42.868\times\dfrac{\pi}{4}\times(5.2\times10^{-2})^2}

v=21.9\ m/s

Hence, The inlet velocity is 21.9 m/s.

The mass flow rate at reach exit is 1.7 kg/s.

7 0
4 years ago
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