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abruzzese [7]
2 years ago
12

During a chemical reaction, the______

Chemistry
2 answers:
kotykmax [81]2 years ago
8 0

Answer:

B) excess reactant

Explanation:

During a chemical reaction, the excess reactant is not fully consumed.

WINSTONCH [101]2 years ago
5 0

Answer:

limiting reagent :)

Explanation:

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wariber [46]

Answer:

Base

Explanation:

4 0
2 years ago
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The flow of energy through living systems can be modeled as food chains, food webs, or energy pyramids. The energy organisms nee
aliya0001 [1]

Answer:

A.......

Explanation:  The sun is the main source of energy

4 0
3 years ago
Someone please help I will give brainliest!!!!!!!
Alex

Answer:

Option 1:

Cu(NO3)2 + Ag

hope this was helpful

7 0
3 years ago
Let's assume you were given 2.0 g benzil, 2.2 g dibenzyl ketone, 50 mL 95% ethanol and 0.3 g potassium hydroxide to synthesize t
almond37 [142]

Answer:

the % yield is 82%

Explanation:

Given the data in the question,

we know that;

Molar mass of benzil is 210.23 g·mol−1

Molar mass of dibenzyl ketone is 210.27 g·mol−1

Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1

Now,

2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole

2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole

3.0 g of tetraphenylcyclopentadienone = 3 / 384.5  = 0.0078 mole

Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone

percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%

= 0.82 × 100%

= 82%

Therefore, the % yield is 82%

3 0
3 years ago
A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of ga
vivado [14]

Answer :  The partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

Explanation : Given,

Moles of X = 2.0 mole

Moles of Y = 6.0 mole

Total pressure = 2.1 atm

Now we have to calculate the mole fraction of X and Y.

\text{Mole fraction of }X=\frac{\text{Moles of }X}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }X=\frac{2.0}{2.0+6.0}=0.25

and,

\text{Mole fraction of }Y=\frac{\text{Moles of }Y}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }Y=\frac{6.0}{2.0+6.0}=0.75

Now we have to calculate the partial pressure of X and Y.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 2.1 atm

X_i = mole fraction of gas

p_{X}=X_{(X)}\times p_T

p_{X}=0.25\times 2.1atm=0.525atm

and,

p_{Y}=X_{(Y)}\times p_T

p_{Y}=0.75\times 2.1atm=1.575atm

Thus, the partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

4 0
3 years ago
Read 2 more answers
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