1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
finlep [7]
3 years ago
13

Who goes to K12 and if so what grade

Chemistry
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

I might next year with my cuz and nex year ima be in 8th

Explanation:

grandymaker [24]3 years ago
5 0

Answer:

Hey! I`m In K12. Currently in 7th, going into 8th next year. I have Mrs. Keefe and one of my teachers, what about y`all?

You might be interested in
What is constant on wet asphalt?
wariber [46]

Answer:

Friction and Automobile Tires. ... On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1

Explanation:

hope this helps

6 0
3 years ago
A reaction that combines simpler reactants to form a new compound is called a
uranmaximum [27]

Answer:

A reaction that combines simpler reactants to form a new compound is called a

<h2>Synthesis reaction.</h2>
6 0
3 years ago
The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C
Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})

1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})

1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})

T₂=371.77 K= 98.62 °C

5 0
3 years ago
12. How is the melting point of a substance related to its freezing point? Both indicate the temperature at which the solid and
krok68 [10]
Both indicate the temperature at which the solid and liquid states of a substance are in equilibrium would be your answer.

This is beacause the melting point of a substance is the same as the freezing point of a substance. At this particular temp, the substance can be either a solid or a liquid. 

hope this helps!
8 0
3 years ago
Read 2 more answers
How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O
damaskus [11]
8 H2= 0.90 g , hope that helps
you with your work 

7 0
3 years ago
Other questions:
  • What are the characteristics shapes of s p and d orbitals
    11·1 answer
  • How many milliseconds (ms) are there in 3.5 seconds (2)
    5·1 answer
  • The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 3.001 g sample of B
    8·1 answer
  • How many atoms of N are in 137.0 grams of N2O3?
    10·2 answers
  • Which organism is able to cause an infection
    9·2 answers
  • A 48.9 g piece of aluminum is dropped in a graduated cylinder partially filled with water. The original volume of water in the c
    8·1 answer
  • Determine the number of miles of C in each sample​
    15·1 answer
  • Convert 7.8 moles of carbon tetrafluoride into grams.
    14·1 answer
  • What are the properties of PLA plastic PLEASE HELP
    6·1 answer
  • Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) Mn²⁺(aq) + BiO₃⁻(aq) → MnO₄⁻(aq) + B
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!