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3 years ago

classify the following elements under metals, non metals and metalloids, boron, zinc Mercury, silicon, oxygen, nitrogen, sodium

Chemistry

1 answer:

myrzilka [38]3 years ago

8 0

Answer:

Zinc mercury transition metal

Silicon boron metalloid

Oxygen nitrogen non metal

Sodium alkali metal

Explanation:

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A bottle contains 175 ml of insulin at a concentration of 40.0 mg/ml . what is the total mass of insulin in the bottle?

Inessa [10]

D - density: 40 mg/ml
V - volume: 175 ml
m - mass: ??
__________
d = m/V
m = V×d
m = 175×40
m = 7000 mg = 7 g

:•)

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4 years ago

What is the molarity of a solution of 0.2 moles of Potassium Oxide

egoroff_w [7]

The molarity of a solution : 0.4 M

<h3>Further explanation</h3>

Given

0.2 moles of Potassium Oxide

500 ml of water = 0.5 L

Required

The molarity

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Assume volume of solution = volume of water(addition of solution volume from volume Potassium Oxide is negligible

Input the value :

M = 0.2 : 0.5

M = 0.4

3 0

3 years ago

Calculate the vapor pressure of spherical water droplets of radius (a) 17 nm and (b) 2.0 μm surrounded by water vapor at 298 K.

Montano1993 [528]

Explanation:

Relation between pressure of water and its droplet is as follows.

$ln (\frac{p}{p_{o}}) = \frac{2 \gamma M}{r \rho RT}$

where, p = pressure of droplet

$p_{o}$ = water pressure in given temperature

$\gamma$ = $7.99 \times 10^{-3}$

M = Molecular Weight in Kg/Mol (0.018 for water)

r = radius in meters

$\rho$ = density of water in $Kg/m^{3}$ (1000 $kg/m^{3}$ )

R = ideal gas constant (8.31)

T = temperature in Kelvin

(a) We will calculate the value of p as follows.

p = $e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}$

= $e^{\frac{2 \times 0.07199 \times 0.018}{1.7 \times 10^{-8} \times 1000 \times 8.31 \times 298 K} \times 25.2$

= 26.8 torr

(b) And, vapor pressure of spherical water droplets of radius 2.0 $\mu m$ or $2 \times 10^{-6} m$

p = $e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}$

= $e^{\frac{2 \times 0.07199 \times 0.018}{2 \times 10^{-6} \times 1000 \times 8.31 \times 298 K} \times 25.2$

= 25.2 torr

7 0

4 years ago

A sample of an ionic compound containing iron and chlorine is analyzed and found to have a molar mass of 126.8 g/mol. what is th

julsineya [31]

Answer is: <span>the charge of the iron in this compound is +2.
Atomic mass of iron is 55,8 g/mol.
Atomic mass of chlorine is 35,5 g/mol.
If compound is FeCl, molar mass would be 55,8 </span>g/mol + 35,5 g/mol = 91,3 g/mo, that is not correct.
If compound is FeCl₂, malar mass of compound would be:
55,8 g/mol + 2·35,5 g/mol = 126,8 g/mol, that is correct.
Oxaidation number of chlorine is -1.

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3 years ago

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Marat540 [252]

D amplitude is the answer

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3 years ago

classify the following elements under metals, non metals and metalloids, boron, zinc Mercury, silicon, oxygen, nitrogen, sodium​

classify the following elements under metals, non metals and metalloids, boron, zinc Mercury, silicon, oxygen, nitrogen, sodium