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Scilla [17]
3 years ago
7

10) Which gas sample at STP has the same number of molecules as a 2.0 Liter

Chemistry
1 answer:
goblinko [34]3 years ago
7 0

Answer:

The sample at STP that has the same total number of molecules as 2.0 liters of CO2(g) at STP is 2) 2.0 L of CI2 (g) New questions in Chemistry Exercise 1-8 Calculate the number of moles of 4.82 x 10 to the power of 24 iron atoms

Explanation:

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A) The equilibrium shifts to the left, producing more H3O+.
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Answer: these are just options, what is the main question, without it, we cannot determine which option is correct, so please repost the question.

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3 years ago
Ch4+202==>c02+302 what type of chemical reaction
n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

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2 years ago
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kiruha [24]

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6 0
2 years ago
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The melting point of phenol is 40.5∘C and that of toluene is −95∘C. What is the best explanation for this difference? Select the
romanna [79]

Answer:

None of the above

Explanation:

The (−OH) group on phenol can form hydrogen bonds, and the −CH3 group on toluene cannot.

Phenol has only one hydrogen on the −OH group available to form hydrogen bonds, so the hydrogen bond is stronger. In toluene, the hydrogen bond is spread over all three hydrogens on the methyl group, so the interaction is weaker overall.

Phenol has a higher molecular mass than toluene.

3 0
3 years ago
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If you have 150. mg of cysteine, how many h atoms are present in your sample?
Archy [21]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of cysteine = 150 mg = 150 x 10⁻³ g
Molar mass of cysteine = 121.16 g/mol
Moles of cysteine = 150 x 10⁻³ g / 121.16 g/mol
                            = 1.238 x 10⁻³ mol

Cysteine has chemical formula as C₃H₇NO₂<span>S.
Hence, 1 mole of </span>C₃H₇NO₂S produces 7 moles of H atoms.
Hence, moles of H atoms present in the sample = 1.238 x 10⁻³ mol x 7
                                                                                 = 8.666 x 10⁻³ mol

According to the Avogadro's constant 1 mole of substance has 6.022 × 10²³ particles.

Hence,
    number of H atoms in the sample = 8.666 x 10⁻³ mol x 6.022 × 10²³ mol
                                                              = 5.219 x 10²¹

8 0
3 years ago
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