Answer:
6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
Explanation:
Given data:
Moles of CuCl₂ = 6 mole
Moles of AlCl₃ produced = ?
Solution:
3CuCl₂ + 2Al → 2AlCl₃ + 3Cu
Now we will compare the moles of CuCl₂ with AlCl₃ .
CuCl₂ : AlCl₃
3 : 2
6 : 2/3 ×6 = 4 mol
So, 6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
Answer:
1086.2 L
Explanation:
The computation of the volume of the elevation is given below:
Here we assume the volume of the elevation be x
As we know that
V¹ ÷ T¹ = V² ÷ T²
Here
V^1 = 1500
T^1 = 290
V^2 = x
T^2 = 210
Now place these values to the above formula
So,
1500 ÷ 290 = x ÷ 210
x = 1086.2 L
Answer :]
A.)Calculate the mass of ammonium sulfate that would be obtained by reacting with ammonia acid.
<em>Correct me if i'm wrong :]</em>
I am pretty sure that the effect on the volume of 1 mol of an ideal gas is being revelesd by the option : B. The pressure changes from 760 torr to 202 kPa, and the temp. changes from 37degrees C to 155 degrees kelvin. I choose this one because you have to use ideal gas law - V= nRT/P and you will see the doubled pressure in here : <span>760 torr= 1atm and 202kPa = 2 atm.
Do hope it helps! Regards.</span>