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ra1l [238]
2 years ago
10

I am unable to understand from question no 3 and I have assignment due :( in 2 days need to do till 9

Physics
1 answer:
ludmilkaskok [199]2 years ago
8 0

Answer:

Oh well have your parents do something bout that. They are there to help you. Or guardian they all shall help you that is what they are there for. They are they to take care of you, answer you questions, and last but not least, they are there to also raise you. Ask you mom, dad, guardian, and maybe even you teacher to post pone the date. Teachers are to help you. Your guardian is to watch you make sure your safe while your parents are away (bascially like raising you). And parents to raise you, make sure you safe, and many other things like to make sure you are fed.

Explanation:

I hope they all have some type of help for you.

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Idaho Jo is doing physics experiments throughout the solar system. She travels to each planet and shoots a potato straight up in
Natalka [10]

Answer:

Mercury / Mars

Explanation:

For an object launched straight upward, the following SUVAT equation can be used

v^2-u^2=-2gh

where

v is the final velocity

u is the initial velocity

g is the acceleration of gravity (free fall acceleration) (the negative sign is due to the downward direction of gravity)

h is the maximum height reached

At the maximum height, the velocity is zero, so v = 0. Re-arranging the equation,

h=\frac{u^2}{2g}

So we see that for equal initial velocity (u), the maximum height reaches is inversely proportional to the acceleration of gravity. Therefore, the potato gun will reach the highest altitude in the planets with lowest acceleration of gravity, therefore Mercury and Mars (3.7 and 3.6 m/s^2).

4 0
3 years ago
The usefulness of blotting techniques in molecular biology is that
densk [106]

Answer:

Transferred material is in the same relative position on the disk as on the original sample

Explanation:

The usefulness of blotting techniques in molecular biology is that transferred material is in the same relative position on the disk as on the original sample

3 0
3 years ago
What type of friction occurs when you are trying to move an object, but the object isnt moving?
Tasya [4]

the answer is static friction


7 0
3 years ago
Along the frictionless path you have chosen, the main force(s) acting on the puck after receiving the kick is (are):
Vaselesa [24]
Gravity, and Normal. Check the comments for why Applied isn't one.
5 0
3 years ago
A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 14.413
natima [27]

Answer:

The value of  charge q₃ is 40.46 μC.

Explanation:

Given that.

Magnitude of net force F=14.413\ N

Suppose a point charge q₁ = -3 μC is located at the origin of a co-ordinate system. Another point charge q₂ = 7.7 μC is located along the x-axis at a distance x₂ = 8.2 cm from q₁. Charge q₂ is displaced a distance y₂ = 3.1 cm in the positive y-direction.

We need to calculate the distance

Using Pythagorean theorem

r=\sqrt{x_{2}^2+y_{2}^2}

Put the value into the formula

r=\sqrt{(8.2\times10^{-2})^2+(3.1\times10^{-2})^2}

r=0.0876\ m

We need to calculate the magnitude of the charge q₃

Using formula of net force

F_{12}=kq_{2}(\dfrac{q_{3}}{r_{3}^2}+\dfrac{q_{1}}{r_{1}^2})

Put the value into the formula

14.413=9\times10^{9}\times7.7\times10^{-6}(\dfrac{q_{3}}{(0.0438)^2}+\dfrac{-3\times10^{-6}}{(0.0876)^2})

(\dfrac{q_{3}}{(4.38\times10^{-2})^2}+\dfrac{-3\times10^{-6}}{(0.0876)^2})=\dfrac{14.413}{9\times10^{9}\times7.7\times10^{-6}}

\dfrac{q_{3}}{(0.0438)^2}=207\times10^{-4}+3.909\times10^{-4}

q_{3}=0.0210909\times(0.0438)^2

q_{3}=40.46\times10^{-6}\ C

q_{3}=40.46\ \mu C

Hence, The value of  charge q₃ is 40.46 μC.

5 0
2 years ago
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