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BabaBlast [244]
3 years ago
14

What is the best definition of a eukaryotic cell?

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

A. has an internal structure consisting of a membrane–bound nucleus and membrane–bound organelles

Explanation:

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How many molecules are in 85 grams of Silver?
densk [106]

Answer:

3.0 × 10

3.0 \times  {10}^{23}

molecules

Explanation:

there are many molecules

8 0
3 years ago
What would you do during a zombie apocalypse
DiKsa [7]

Answer:

I would love to say C but I know me so A

7 0
3 years ago
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How many atoms of each element are in NaCI?<br><br><br> |___| sodium <br><br> |___| chlorine
gogolik [260]

Answer:

There are 2 atoms in NaCl. This is because there is 1 atom of Na (sodium) and 1 atom of Cl (chlorine) in each NaCl molecule. Elements by themselves do not have a "number of atoms"- if you're talking about the atomic number, it's the number of protons (or electrons in a neutral atom) of an element.

7 0
2 years ago
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Ex 1) 45.2 g of Zn = _____ moles Zn<br><br> Ex 2) 0.568 moles Ag = _____ grams Ag
Jlenok [28]

the molar mass of Zn is 65

  • number of mole(n)=reacting mass/molar mass
  • n=45.2/65
  • =0.70g/mol

2.the molar mass of Ag is 108

  • 0.568=m/108
  • then cross multiply
  • m=0.568×108
  • m=61.3g
5 0
3 years ago
3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with
ira [324]

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

7 0
3 years ago
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