Answer:
The answer to your question is below
Explanation:
Process
1.- Look for the longest chain
2.- Number the carbons of the main chain starting from the corner where the double bond is closer.
3.- Circle the branches
4.- Start naming the number where the branch is and the name of the branch.
5.- Name the main branch with the ending -ene.
5-methyl, 1-hexene or 5-methyl, hex-1-ene
See gthe structure below.
Answer:
Family, Friends, and food?
Explanation:
sorry if its wrong, i did something like this last year, and this was my answer so sorry if its wrong TwT
Answer:
0.54 mole
Explanation:
CH3COOH CH3CH2OH CH3COOCH2CH3 H2O
Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol
Change - x - x + x + x
Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)
K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]
x*(1.0+x)/(1.0-x)(1.0-x) = 4.0
x+x²=4*(1-x)²
x+x² = 4(1² - 2x + x²)
x + x² = 4 - 8x + 4x²
4 - 8x + 4x²- x² - x= 0
3x² - 9x + 4 = 0
x=2.5 , x=0.54
2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,
so answer is 0.54 mole.
%error = |(original value - mistaken value)| / original value * 100%
Original value = 1.2 x 10^-12
Mistaken value = 1.7 x 10^-10
%error = | [(1.2 x 10^-12) - (1.7 x 10^-10)] | / 1.2 x 10^-12 x 100%
%error = (1.688 x 10^-10 / 1.2 x 10^-12) x 100%
%error = 1.172222222 x 10^17
Answer:
306.6g/mol
Explanation:
To calculate molecular weight you need to know how many grams ou have in a determined amount of moles of substance. As you have the mass of the sample (1.42g), you need to find how many moles are, as follows:
The reaction of the acid HX with the base YOH is:
HX + YOH → H₂O + YX
<em>1 mole of acid reacts per mole of base.</em>
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In a titration, the solution turned pink when moles base = moles acid.
Moles of base that the student added (Using the volume and molarity of the solution) are:
32.48mL = 0.03248L ₓ (0.1426 moles base / L) = 0.004632 moles of base
As the titration is in equivalence point, there are 0.004632 moles of the acid
Molecular weight (Ratio between grams of sample and its moles) is:
1.42g / 0.004632 moles =
<h3>306.6g/mol</h3>