Answer is: <span>mass of calcium carbonate needed is 120 grams.
</span>Chemical reaction:
CaCO₃(s) → CaO(s) + CO₂(g)<span>.
</span>V(CO₂) = 27.0 L.
Vm = 22.4 L/mol.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 27 L ÷ 22.4 L/mol.
n(CO₂) = 1.2 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
m(CaCO₃) = 1.2 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 1.2 mol · 100 g/mol.
m(CaCO₃) = 120 g.
Answer:
6,41 min
Explanation:
For the reaction:
A → products
kinetics first-order reaction law is:
ln[A] = ln[A]₀ -kt
Where [A] is concentration of reactant, [A]₀ is initital concentration of reactant, k is rate constant and t is time.
If the concentration of A is 6,25% you can assume:
[A] = 6,25; [A]₀= 100. Replacing:
ln(6,25) = ln(100) -7,20×10⁻³s⁻¹t
-2,7726 = -7,20×10⁻³s⁻¹t
385s = t
In minutes:
385s×
= <em>6,41 min</em>
<em></em>
I hope it helps!
When 67 g of water is heated from its melting point to its boiling point, it takes 28006 J of heat.
<h2>Relationship between heat production and temperature change</h2>
- A way to numerically relate the quantity of thermal energy acquired (or lost) by a sample of any substance to that sample's mass and the temperature change that results from that is provided by specific heat capacity.
The following formula is frequently used to describe the connection between these four values.
q = msΔT
where, q = the amount of heat emitted or absorbed by the thing
m = the object's mass = 67 gm
s = a specific heat capacity of the substance = 4.18 J/gC
ΔT = the resultant change in the object's temperature = 373.15 -273.15K= 100 k
q = 67 * 4.18 * 100 J
⇒q = 28006 J
Therefore it is concluded that 67 g of water takes 28006 J of heat from its melting point to reach its boiling point.
Learn more about thermal energy here:
brainly.com/question/3022807
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Answer:
An aluminium drink can.
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