Answer:
Buoyant force which is equal in magnitude to the fish's weight
Explanation:
A fish floating motionless below the surface of a lake, is an equilibrium position with the water.
Hence, upward force must be equal to downward force.
The downward force is due to fish's weight while the buoyant force is the upward force due to force of the water.
The answer is B. 79 joules.
To calculate this we will use the formula for potential energy (PE):
PE = m * g * h
where m is mass of an object, g is gravitational acceleration, h is a height at which is the object.
It s given:
m = 8.10 kg
g = 9.8 m/s²
h = 0.99 m
After replacing them in the formula for potential energy:
PE = 8.10 * 9.8 * 0.99 = 78.6 J ≈ 79 J
Answer:
Image
Explanation:
I looked at the graph and assumed answers
Answer:
<em>20m/s</em>
Explanation:
Given
Velocity = 40m/s
angle = 30°
Vertical component = Vsin theta
Substitute into the formula
Vy = 40sin30
Vy = 40(0.5)
Vy = 20m/s
<em>Hence the vertical component of the velocity right before the ball hits the ground is 20m/s</em>
The gravitational potential energy of the rock is:
490 J at 50 m
196 J at 20 m
9.8 J at 1 m
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field.
For an object near the Earth's surface, the GPE is given by
where
m is the mass of the object
is the acceleration of gravity at Earth's surface
h is the heigth of the object relative to the ground
For the rock in this problem,
m = 1 kg
So its GPE at h = 50 m is
The GPE at h = 20 m is
While the GPE at h = 1 m is
Learn more about gravitational potential energy:
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