Select the correct answer.

A 1,450 kg car drives toward a 60 kg shopping cart that has a velocity of -1.2 m/s toward the car. The two objects collide, givi

Y_Kistochka [10]

Answer:

A) v₁ = 5.66 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conservation before and after a collision.

The linear momentum is equal to the mass by the product of the Velocity.

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now, to the right side of the equal sign will take the linear momentum before the collision and to the left side of the equal sign as after the collision.

Pbefore = Pafter

(m₁*v₁) - (m₂*v₂) = (m₁*v₃) + (m₂*v₄)

where:

m₁ = mass of the car = 1450 [kg]

v₁ = velocity of the car before the collision [m/s]

m₂ = mass of the shopping cart = 60 [kg]

v₂ = velocity of the shopping cart before the collision = -1.2 [m/s]

v₃ = velocity of the car after the collision = 5.13 [m/s]

v₄ = velocity of the shopping cart after the collision = 11.75 [m/s]

Now replacing:

(1450*v₁) - (60*1.2) = (1450*5.13) + (60*11.75)

1450*v₁ - 72 = 7438.5 + 705

1450*v₁ = 7438.5 + 705 + 72

1450*v₁ = 8215.5

v₁ = 5.66 [m/s]

4 0

3 years ago

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A mechanic pushes a 2.60 ✕ 103-kg car from rest to a speed of v, doing 5,430 J of work in the process. During this time, the car

Oduvanchick [21]

Part A. We are given that a car is pushed from rest to a final speed doing 5430 Joules of work. -

To determine the final velocity we will use the work and energy theorem which states that the work done is equal to the change in kinetic energy:

$W=K_f-K_0$

Since the car starts from rest this means that the initial kinetic energy is zero:

$W=K_f$

The kinetic energy is given by:

$K=\frac{1}{2}mv^2$

Substituting in the formula we get:

$W=\frac{1}{2}mv_f^2$

Now, we solve for the final velocity. First, we multiply both sides by 2 and divide both sides by the mass:

$\frac{2W}{m}=v_f^2$

Now, we take the square root to both sides:

$\sqrt{\frac{2W}{m}}=v_f$

Now, we plug in the values:

$\sqrt{\frac{2(5430J)}{2.6\times10^3kg}}=v_f$

Solving the operations:

$2.04\frac{m}{s}=v_f$

Therefore, the final velocity is 2.04 m/s.

Part B. Now, we use the following formula for work:

$W=Fd$

Where "F" is the force and "d" is the distance.

Now, we set this equation equal to the work done by the force:

$Fd=5430J$

Now, we divide both sides by the distance "d":

$F=\frac{5430J}{29m}=187.2N$

Therefore, the force exerted is 187.2 Newton.

7 0

2 years ago

Suppose a plot of inverse wavelength vs frequency has slope equal to 0.119, what is the speed of sound traveling in the tube to

strojnjashka [21]

Answer:

8.40 m/s

Explanation:

Slope of the plot is 0.119

Slope of a plot is given by the change in y direction divided by the change in x direction

Here, the y axis represents inverse wavelength and the x axis represents frequency.

f = Frequency (Hz, assumed)

v = Phase velocity (m/s, assumed)

λ = Wavelength (m, assumed)

So, slope

$m=\frac{\frac{1}{\lambda}}{f}$

Now,

$\lambda=\frac{v}{f}\\\Rightarrow \lambda^{-1}=\frac{f}{v}$

$\\\Rightarrow m=\frac{\frac{f}{v}}{f}\\\Rightarrow 0.119=\frac{1}{v}\\\Rightarrow v=\frac{1}{0.119}\\\Rightarrow v=8.40\ m/s$

The speed of sound travelling in the tube is 8.40 m/s

5 0

4 years ago

Why does your weight change on the moon

lorasvet [3.4K]

Answer:

the moon has different gravitational force.

5 0

3 years ago

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If a bag of pretzels says it contains 10 servings, and each serving is 150 calories, how many calories would you consume if you

Sindrei [870]

Answer:

5400

Explanation:

i calculated it

Big brain

8 0

3 years ago