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motikmotik
3 years ago
12

Consider the statement, “In a chemical reaction, atoms are neither created nor destroyed, only rearranged.” Why is this a statem

ent of the law of conservation of mass?
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer: The law of conservation of mass is reffering to the fact that energy cannot be created or destroyed. So when you speak about atoms not being created or destroyed it is the same thing. Unless you're talking about an atomic bomb where the atoms are split.

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Ne

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A 253 g block of wood has the following dimensions: Length 15.24 cm Width 6.64 cm Height 3.56 cm What is the density of the wood
yanalaym [24]

Answer:

0.7 g/cm³

Explanation:

<em>hey there,</em>

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< The formula for density is p = \frac{m}{v}  where m = mass, v = volume, and p = density. An easy way to remember the formula is density equals love. I found this easy to remember because p = ♡ and when you think about it, if you split the heart in half through the middle like a fraction, it will make \frac{m}{v} (if you don't understand what I'm saying, try writing it out and you will be able to see what I'm talking about!)

We already know that the block is 253 g so the mass is 253 g.

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15.24 cm x 6.64 cm x 3.56 cm = 360.25 cm³

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A process at constant T and P can be described as spontaneous if ΔG &lt; 0 and nonspontaneous if ΔG &gt; 0. Over what range of t
creativ13 [48]

Answer:

Incomplete question, it is lacking the data it makes reference. The missing data from Chegg is:

                              2 SO3(g)   →          2 SO2(g) + O2(g)

ΔHf° (kJ mol-1)  -395.7                        -296.8

S° (J K-1 mol-1)  256.8                         248.2              205.1

ΔH° =  kJ

S° =  J K⁻¹

Explanation:

The method to solve this problem calls for the use of the Gibbs standard free energy change:

ΔG = ΔrxnH - TΔSrxn

We know a reaction is spontaneous when ΔG is < 0, so to answer this question we need to solve for the temperature, T, at which ΔG becomes negative.

Now as mentioned in the hint, we need to determine  ΔrxnH and ΔSrxn, which are given by

ΔrxnH = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where  ν  is the stoichiometric coefficient in the balanced chemical equation.

For ΔS we have likewise

ΔrxnS =  ∑ ν x ΔSº products - ∑ ν x ΔSº reactants

Thus,

ΔrxnH(kJmol⁻¹) =  2 x (-296.8) - 2 x ( -395.7 ) = 197.8 kJ

ΔrxnS ( JK⁻¹) = 2 x 248.2 + 205.1 - 2 x 256.8 = 187.9 JK⁻¹ = 0.1879 kJK⁻¹

So ΔG kJ =  197.8 - T(0.1879)

and the reaction will become spontaneous when the term  T(0.1879)  becomes greater that 197.8,

0 = 197.8 - 0.1879 T  ⇒ T = 1052 K

so the reaction is spontaneous at temperatures greater than 1052 K (780 ºC)

4 0
3 years ago
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