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ryzh [129]
3 years ago
14

Examine the given reaction.

Chemistry
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

The correct option is;

D)

Explanation:

The given reaction is presented as follows;

NH₄Cl (s) → NH₃ (g) + HCl (g) ΔH° = 176 kJ/mol, ΔS° = 0.285 kJ/(mol·K)

We note that the Gibbs free energy, ΔG° is represented by the following equation;

ΔG° = ΔH° - T·ΔS°

Where:

T = Temperature (Kelvin)

The reaction will be spontaneous for exergonic reactions, ΔG° < 0 and it will not be spontaneous for endergonic reaction, ΔG° > 0

At room temperature, T = 25 + 273.15 = 298.15 K

Which gives;

ΔG° = 176  - 298.15 × 0.285 = 91.03 kJ/mol which is > 0 Not spontaneous reaction

At 800°C, we have;

T = 273.15 + 800°C  + 1073.15 K

ΔG° = 176  - 1073.15 * 0.285 = -129.85 kJ/mol which is < 0 the reaction will be spontaneous

The correct option is therefore, that at room temperature, the reaction is not spontaneous. However, at high temperatures. like 800 °C, the free energy value turns negative and this reaction becomes spontaneous.

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n = m / M

Where, n is moles of the compound (mol), m is the mass of the compound (g) and M is the molar mass of the compound (g/mol)

Here, the given ethanol mass = 50.0 kg = 50.0 x 10³ g

Molar mass of the ethanol = (12 x 2 + 1x 6 + 1 x 16) g/mol
                                          = 46 g/mol

Hence, moles in 50.0kg of ethanol = 50.0 x 10³ g / 46 g/mol
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3 0
3 years ago
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gulaghasi [49]
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In a reaction between 6.0 g of oxygen gas, 4.0 g of hydrogen gas, and 5.0 g of solid sulfur at standard temperature and pressure
nikitadnepr [17]

Answer:

The limiting reagent is the O₂

Explanation:

We can think, this reaction

2O₂(g) + H₂(g) + S(s)  →  H₂SO₄

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6 g / 32 g/m = 0.187 mole O₂

4g / 2 g/m = 2 mole H₂

5g / 32.06 g/m = 0.156 mole S

Ratio between reactants is 2:1:1, 1:2:1, 1:1:2

For 2 mole of O₂, I need to react 1 mol of H₂ and 1 mol of S

0.187 mole of O₂, I need (the half)

0.093 mole of H₂ and 0.093 mole of S

For 1 mole of H₂, I need to react 2 mole of O₂ and 1 mol of S

2 mole of H₂, I need (the double of O₂ and the same for S)

4 mole of O₂ ; 2 mole of S

For 1 mol of S, I need to react 1 mol of H₂ and 2 mole of O₂

0.156 mole I need the same amount for H₂ and the double for O₂

0.156 mole of H₂ and 0.312 mole of O₂

In both cases, I can't make react, all the mass of oxygen, so this is the limiting reagent.

6 0
3 years ago
PLZ HELP. Write and balance the following chemical equations:
zubka84 [21]

Answer:

No they form nitrogen oxide which can be poisonous to some species but depending on the amount of nitrogen it can be harmful to everything living. Such as if you put it with a plant that had low nitrogen levels then there would be no carbon dioxide to filter.

Explanation:

6 0
2 years ago
What is the solubility of NH4CL at 50 degrees C?
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i believe its 50 grams.

8 0
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