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Sergeu [11.5K]
2 years ago
12

Dissolving 3.0 g of CaCl2(s) in 150.0 g of water in a calorimeter at 22.4 o C causes the temperature to rise to 25.8 o C. What i

s the approximate amount of heat involved in the dissolution, assuming the specific heat of the resulting solution is 4.18 J/g o C? Is the reaction exothermic or endothermic?
Chemistry
1 answer:
pentagon [3]2 years ago
7 0

Answer:

Explanation:

Heat involved Q = mcΔt where m is mass , c is specific heat of water and Δt is rise in temperature

= 150 x 4.18 x 25.8 J .

= 16176.6 J .

As the temperature rises , the reaction is exothermic.

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If the volume of a confined gas is doubled while the temperature remain constant, what change (if any) would be observed in the
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The gas will obey Boyles Law:

P1 V1 = P2 V2      where P1 and V1 are the original pressure and volume and P2 and V2 are the new  values.

If V2 = 2V1  (given) then:

P1 V1 = P2 *2 V1

P2 = P1 V1 / 2V1

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The osmotic pressure of a saturated solution of strontium sulfate at 25 ∘C∘C is 21 torrtorr. Part A What is the solubility produ
USPshnik [31]

Answer

solubility product = 3.18x 10^-7

Explanation:

We were given the pressure in torr then we need to convert to atm for consistency, ten we have

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for XY vanthoff factor i = 2

S = 0.0821 L-atm / mol K

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M = 0.000564698046 mol/liters

solubility= 0.000564698046 mol/liters

Ksp = [X+][Y-]

Ksp = X^2

Ksp = [Sr^+2] * [SO4^-2]

Ksp = X^2

Ksp = (0.000564698046)^2

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