1.
The equation for this problem would be
y = (?)x + 190
With y being the height after a given amount of years and x being the amount of years passing. We would need to find ?, the rate of how fast the tree grows. The problem gives us y = 274 centimeters and x = 3 years
Let’s plug in and solve for ?
274 = ?(3) + 190
84 = ?3
28 = ?
The tree grew 28 cm per year
2.
Since we know the rate of change and y, let’s just plug in values
344 = 28x + 190
154 = 28x
5.5 = x
5.5 years since Renata moved.
For this problem, we know d = 6 because (11 - 5) = (17 - 11) = (23 - 17) = 6
Now, we have to use the formula:
For this problem, d = 6 and a(base1) is 5, so plug it in like this:
To simplify, all you have to do is distribute the six and reduce like so:
So, here's your answer:
Hope this helps!
Answer:
Object will reach the max height in 10 seconds.
Max. height is 1817.
It will hit the ground in 20 seconds.
Step-by-step explanation:
In order to find the x value which makes the function take its greatest value, you need to take the derivative of the function and equalize the result to 0.
h'(t)=-12t+120=0
t=10
The object will reach its maximum height in 10 seconds.
h(10) (maximum height) = 6.10.10+120.10+17= 600+1200+17=1817
Considering this is a parabola, time in total is two times more than the time passed until reaching the max. height.
10.2=20
√38
Let's name all the squares.
1² = 1 x 1 = 1
2² = 2 x 2 = 4
3² = 3 x 3 = 9
4² = 4 x 4 = 16
5² = 5 x 5 = 25
6² = 6 x 6 = 36
7² = 7 x 7 = 49
8² = 8 x 8 = 64
Okay that's far enough. Now we look for which numbers 38 is in between.
That would be 36 and 49.
But it's asking for where the square root of 38 is, so √36 and √49 ⇒ 6 and 7.
Answer:
Step-by-step explanation:
Hope it is helpful....
