Answer:
The electric field does positive work on the charge.
The potential energy associated with the charge decreases.
Explanation:
We know that force due to electric filed on a charge particle q given as
F = q E --------1
If the positive charge is moving in the direction of electric filed it means that force due to electric field and displacement of particle due to motion is in the same direction.So the work done due to electric filed will be positive.
Work = Force . Displacement
W= F.d
F= W/d ---------2
From equation 1 and 2
W/d = q E
W/ q = E/ d
We know that voltage difference ΔV
ΔV = E/ d
ΔV =W/ q
So the potential difference will be decrease because charge is positive.So the potential energy will be decreases.
Becomes numb. Or begins to hurt
Density = Mass / Volume
Volume = Area x Length = (4.50 x 5.20) x 6.00 = 140.4
Density = 1587 x 140.4 = 222,814.8 g/cm3 (cubed)
222,814.8 / 1000 = 222.8148 kg/m3 (cubed)
Assuming that all energy of the small ball is transferred
to the bigger ball upon impact, then we can say that:
Potential Energy of the small ball = Kinetic Energy of
the bigger ball
Potential Energy = mass * gravity * height
Since the small ball start at 45 cm, then the height
covered during the swinging movement is only:
height = 50 cm – 45 cm = 5 cm = 0.05 m
Calculating for Potential Energy, PE:
PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J
Therefore, maximum kinetic energy of the bigger ball is:
<span>Max KE = PE = 0.98 J</span>
Change in volume = mass x coefficient of linear expansion x change in temperature
.002 x .0001802 x 30 = .000010812
initial volume + change in volume = Final volume
.002 + .000010812 = .002010812 m cubed
