The following are the four forces acting on the amino acids placed in water:
1. Van der Waals forces: The natural stickiness of every single atom, resulting due to the movement of its electron cloud.
2. Electrostatic charge: The ions of a side chain, which have either minus or plus charge.
3. S-S bonds: Many sulfur-containing amino acids like cysteine situated in the distinct parts of the protein chain, associated with each other, forming a covalent bond, which connects together the two distinct parts of a protein molecule.
4. Hydrogen bonds: As the oxygen of the water molecule is strong, it pulls the electron cloud away from its two hydrogens, making its hydrogen somewhat positive and thus possessing the tendency to associate with the negative poles on the adjacent molecules.
Hydrophobic is defined as the tendency to repel or fail to mix with water. While hydrophilic is defined as possessing the tendency to mix with or dissolve in water.
Hydrophilic amino acids are water-loving, while hydrophobic amino acids are water-hating. Hydrophilic amino acids will react in a manner, which is contrasting from their response to water. When positioned in oil, they will be more fascinated with each other in comparison to the surrounding molecules. The non-polar hydrophobic amino acids will not be herded in combination by the oil, as they were by water, so they will get dissolve efficiently.
Answer:
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Explanation:
Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
the kinetic energy is the same as the canoes weight times its speed times the force of gravity.
Answer:
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
Step 1: Data given
Nitric acid = HNO3
Molar mass of H = 1.01 g/mol
Molar mass of N = 14.0 g/mol
Molar mass O = 16.0 g/mol
Number of moles nitric acid (HNO3) = 0.25 moles
Molairty = 0.10 M
Step 2: Calculate molar mass of nitric acid
Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)
Molar mass HNO3 = 1.01 + 14.0 + 3*16.0
Molar mass HNO3 = 63.01 g/mol
Step 3: Calculate mass of solute use
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.25 moles * 63.01 g/mol
Mass HNO3 = 15.75 grams
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
