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aniked [119]
3 years ago
10

The volume of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is equal to

mL. Report your answer to 4 significant figures in decimal notation (not scientific or exponential notation).
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

.

.

Explanation:

´.

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Which area of the periodic table has the most elements included within it?
hjlf

The area of the periodic table that has the most elements included within it is metals (option A).

<h3>What is periodic table?</h3>

Periodic table of elements is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).

The periodic table encompasses chemical elements arranged horizontally and vertically. The periodic table is made up of groups and periods.

However, most of the elements on the periodic table are metals because virtually 93 elements are metals.

Therefore, the area of the periodic table that has the most elements included within it is metals.

Learn more about periodic table at: brainly.com/question/11155928

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4 0
2 years ago
Draw the circuit symbol that would represent the 9V battery
lora16 [44]
I hope this picture helps

3 0
2 years ago
Scientists' belief that an atom is a solid sphere, is good enough to explain; PLZ I HAVE LESS TIME!!!!
Natasha2012 [34]

Answer:

Its quite vague, instead you could say an atom is the smallest building block which further consists of subatomic particles like protons, neutrons and electrons :)

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7 0
3 years ago
Technetium-104 has a half life of 18.0 minutes. how much of a 165.0 g sample remains after 90.0 minutes?
11Alexandr11 [23.1K]

The mass of 165.0 g sample that remains after 90.0 minutes is 5.16 grams

calculation

lambda㏑2/18= 0.0385

m(t)= 165 x e( 0.0385 x90)  =5.16g

8 0
3 years ago
Read 2 more answers
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
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