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aniked [119]
2 years ago
10

The volume of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is equal to

mL. Report your answer to 4 significant figures in decimal notation (not scientific or exponential notation).
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

Answer:

.

.

Explanation:

´.

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What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?
tiny-mole [99]

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

8 0
3 years ago
Which is NOT a chemical reaction?
Sophie [7]
A is correct because there is no reaction involved
6 0
3 years ago
Read 2 more answers
Sodium thiosulfate, na2s2o3, is used as a "fixer" in black and white photography. identify the reducing agent in the reaction of
aev [14]
Answer is: reducin agent in this reaction is thiosulfate (S₂O₃²⁻).
Balanced chemical reaction: 2S₂O₃²⁻(aq) + I₂(aq) → S₄O₆²⁻(aq) + 2I⁻<span>(aq).
Reducing agent is element or compound who loose electrons in chemical reaction. Sulfur in </span>thiosulfate change oxidation number from +2 to +5 tetrathionate anion (two<span> sulfur </span>atoms in the ion have oxidation state<span> 0 and two atoms have oxidation state +5).</span>
8 0
3 years ago
In Rutherford's Gold foil experiment, were the alpha particles directed to different areas of the gold foil or only the same spo
MrRissso [65]

Answer:

See explanation

Explanation:

In the Rutherford experiment, alpha particles were directed at the same spot on a thin gold foil.

As the alpha particles hit the foil, most of the alpha particles went through the foil. In Rutherford's interpretation, most of the particles went through because the atom consisted largely of empty space.

However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.

This accounted for their scattering through large angles throughout the foil in all directions.

8 0
3 years ago
Select the correct answer from each drop-down menu.
earnstyle [38]

Answer:

The granite block transferred <u>4080 joules</u> of energy, and the mass of the water is <u>35.84 grams</u>.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

<u>Part #1:</u>

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

<u>Part #2:</u>

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

4 0
2 years ago
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